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Anabelle37

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**URGENT - related rates pool problem**

## Homework Statement

A swimming pool with a rectangular surface 18 m long and 12m wide is being filled at the rate of 0.8 cubic metres/min. At one end the pool is 1m deep and at the other end it is 2.5m deep, with a constant slope between the ends. How fast is the height of the water rising when th depth of water at the deep end is 1m?

## Homework Equations

## The Attempt at a Solution

So i have dV/dt = 0.8 and i know i want to find dh/dt when h=1m from deep end.

dV/dt=dV/dh * dh/dt

The total volume of pool = 12*18*18*.5*1.5*18 = 52488 m^3

I'm having trouble working out the V in terms of h as the depth is different and different ends of the pool. Please help, this is for revision for an exam!

Thanks