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Solve using implicit differentiation 6 y+8 x=\sin(xy^2)

  1. Oct 7, 2009 #1
    so to solve this i differentiated each part and got 6dy/dx + 8 = cos(xy^2)(y^2*x2ydy/dx)

    then i divided both sides by cos(xy^2)
    then serpatated the 6dy/dx + 8 and put them both over cos(xy^2)
    then i took out a yprime

    and ended up with

    -8/(6-2y^3xcos(xy^2)) as an answer but its wrong
    can anyone point out where i made a mistake or give me a hint in the right direction?
     
  2. jcsd
  3. Oct 7, 2009 #2
    ((y^2) PLUS 2(dy/dx))

    EDIT: Fixed a mistake.
     
    Last edited: Oct 7, 2009
  4. Oct 7, 2009 #3
    yea thanks, i saw that after looking at the problem again
     
  5. Oct 7, 2009 #4
    you mean y^2x + 2y(dy/dx)?
    isnt it y^2+x2y(dy/dx) since the derivative of x is 1 so the first part is just y^2?
     
  6. Oct 7, 2009 #5
    Oh yes, you're right, my mistake. :)
     
  7. Oct 7, 2009 #6
    So were you able to get the problem right after that?
     
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