Solve Vx in Nodal Voltage Analysis

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SUMMARY

The discussion focuses on solving for Vx in a nodal voltage analysis problem. Participants clarify the equations needed to find Vx, specifically identifying the relationships between voltages V1, V2, and V3. The correct formulation of the equations is established, particularly highlighting the equation (V1-V2)/2 = (V2-V3)/1 + (V2-0)/1, which is crucial for solving the problem. The participants confirm the need for a third equation to complete the analysis, ultimately leading to the solution for V2 and Vx.

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Gclip5
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Homework Statement


Find Vx.
http://imageshack.com/a/img853/3093/ssdr.png

Homework Equations


NONE


The Attempt at a Solution


I just need one more equation so far I have:
1. V1 = 4v
2. V3 = 2Vx
3. (V1-V2)/2 = V2-V3+V2
 
Last edited by a moderator:
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Gclip5 said:

3. (V1-V2)/2 = V2-V3+V2

You made a error

(V1 - V2)/2Ω = V2/1Ω + ??
 
Last edited:
I don't see the error. The voltage is dropping across the resistor from V2 to V3. Likewise for the other one ohm resistor from V2 to ground.
 
Gclip5 said:

3. (V1-V2)/2 = V2-V3+V2

How can this be true if the left side of a the equation has a unit of Amps.
(V - V)/Ω = V/Ω = A
But on the right side you only have a voltage.
And as we all know Ampere are not equal to Volts
 
Jony130 said:
How can this be true if the left side of a the equation has a unit of Amps.
(V - V)/Ω = V/Ω = A
But on the right side you only have a voltage.
And as we all know Ampere are not equal to Volts

Well I guess the equation he meant to write is:

(V1-V2)/2 = (V2-V3)/1 + (V2-0)/1 which is equal to (V1-V2)/2 = V2-V3 + V2
 
Yeah sorry about the poor labeling, but Nugso is correct. I still can't figure out a third equation to get.
 
Ok I see the problem.
So all you need is this

(V1-V2)/2 = (V2-V3)/1 + (V2-0)/1 (1)

2Vx = V3 = 2(V1 - V2) (2)

And you solve for V2.
 
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THANKS. Can't believe i didnt see that.
 

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