 #1
 11
 1
Homework Statement
[/B]
Determine, Using the values given in TABLE A, the current I in the circuit of figure 2 by
(a) Mesh analysis
(b) Nodal analysis
Circuit diagram and given variable attached.
V1 = 120
V2 = j120
V3 = 14.142+j14.142
Z1= 2
Z2=J5
Z3=4
Z4=J5
Z5=J4
Homework Equations
[/B]
KVL
KCL
Ohms law
Supernode
The Attempt at a Solution
[/B]
(a) complete, answer (9.2+j17.2)
(b)
Ref node 0 on bottom line of diagram.
Node V10 between V1 and Z1 = 120V
Node V40 between V2 and Z3 = j120
Node V20 between V3, Z4 and Z1
Node V30 between V3, Z5 and Z3.
Replace V30 with super node. V20V3)
(V1V20/Z1)+(0V20/Z4)+((V20V3/Z5)+(V2(V20V3/Z3)=0
(V1V20/Z1)  (V20/Z4) + (V3V20/Z5) + (V2V20+V3/Z3) = 0
V20(1/Z1+1/Z4+1/Z5+1/Z3) + (V1*1/Z1) + (V2*1/Z3) + (V3*1/Z3) + (V3*1/Z5) = 0
V20((1/2)+(1/j5)+(1/j4)+(1/4) + (120*(1/2)+(V2*1/4)+(14.142+j14.142*1/4)+(14.142+j14.142*1/j4)=0
V20(0.75+j0.05) + (60+j37.071)=0
(60+j37.071)=V20(0.75+j0.05)
V20 = (60+j37.071)/(0.75+j0.05)
V20 = (82.9266 +j43.8996)
V20/Z4 = I
i =8.77992 +j16.5853. Which is off from my mesh answer. working backwards i expected due to the current from the mesh answer, times Z4 to be looking for a V20 voltage of (86+j46) can anyone help. Thanks in advance.
Attachments

23 KB Views: 434
Last edited by a moderator: