- #1

- 11

- 1

## Homework Statement

[/B]

Determine, Using the values given in TABLE A, the current I in the circuit of figure 2 by

(a) Mesh analysis

(b) Nodal analysis

Circuit diagram and given variable attached.

V1 = 120

V2 = j120

V3 = 14.142+j14.142

Z1= 2

Z2=-J5

Z3=4

Z4=-J5

Z5=J4

## Homework Equations

[/B]

KVL

KCL

Ohms law

Supernode

## The Attempt at a Solution

[/B]

(a) complete, answer (-9.2+j17.2)

(b)

Ref node 0 on bottom line of diagram.

Node V10 between V1 and Z1 = 120V

Node V40 between V2 and Z3 = j120

Node V20 between V3, Z4 and Z1

Node V30 between V3, Z5 and Z3.

Replace V30 with super node. V20-V3)

(V1-V20/Z1)+(0-V20/Z4)+(-(V20-V3/Z5)+(V2-(V20-V3/Z3)=0

(V1-V20/Z1) - (V20/Z4) + (V3-V20/Z5) + (V2-V20+V3/Z3) = 0

-V20(1/Z1+1/Z4+1/Z5+1/Z3) + (V1*1/Z1) + (V2*1/Z3) + (V3*1/Z3) + (V3*1/Z5) = 0

-V20((1/2)+(1/-j5)+(1/j4)+(1/4) + (120*(1/2)+(V2*1/4)+(14.142+j14.142*1/4)+(14.142+j14.142*1/j4)=0

-V20(0.75+j0.05) + (60+j37.071)=0

(60+j37.071)=V20(0.75+j0.05)

V20 = (60+j37.071)/(0.75+j0.05)

V20 = (82.9266 +j43.8996)

V20/Z4 = I

i =-8.77992 +j16.5853. Which is off from my mesh answer. working backwards i expected due to the current from the mesh answer, times Z4 to be looking for a V20 voltage of (86+j46) can anyone help. Thanks in advance.

#### Attachments

Last edited by a moderator: