Solve Wave Equation with D'Alembert's Solution

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actionintegral
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Friends,

I have seen the wave equation solved by changing the coordinates to
u=x+ct and v=x-ct.

This is preposterous! Solve the wave equation by moving at the speed of light! Outlandish!
 
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Use the relativistic D'Alembert's solution then..
 
Solution to what?
 
actionintegral said:
Friends,

I have seen the wave equation solved by changing the coordinates to
u=x+ct and v=x-ct.

This is preposterous! Solve the wave equation by moving at the speed of light! Outlandish!
Um, the 'c' is just the speed appearing in the wave equation:

[tex]\frac{\partial^2 f}{\partial x^2}=\frac{1}{c^2}\frac{\partial^2 f}{\partial t^2}[/tex]

Could be the speed of sound or whatever. It depends on what the speed 'c' in your wave equation is.
 
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Yes. Suppose c is the speed of sound. What is the effect of setting
u=x-ct? You are changing to a frame that is traveling at the speed of sound. Suppose c is the speed of light. What is the effect of setting u=x-ct? You are changing to a frame that is traveling at the speed of ... of ...
 
Fair enough. Let me counter. Suppose I solve a physics problem by changing to a frame where
x= .99ct Can I do so with a clear conscience?
 
You're not 'changing to a frame'. You introduce new variables u and v to help solve the differential equation. It's mathematics, not physics. Mathematically you can make c 20 times the speed of light and you'll still get a solution to the differential equation in the form F(x+ct)+G(x-ct). In a relativistic physical theory you wouldn't find something that obeys that wave equation with c greater than lightspeed so that's not an issue.
 
Galileo said:
You're not 'changing to a frame'.

I understand perfectly now. Saying "my friend is at x=5" and then saying "let u=x-5. My friend is at u=0" is distinct from saying "I am where my friend is".

That said, maybe someone can help me understand the d'alembert solution to the schroedinger equation. I did this with u=x+ct, v=x-ct.
Then I got nervous and changed the "c" to a "v".

Now I don't know what the h******ell to think.:confused:
 
actionintegral said:
Yes. Suppose c is the speed of sound. What is the effect of setting
u=x-ct? You are changing to a frame that is traveling at the speed of sound. Suppose c is the speed of light. What is the effect of setting u=x-ct? You are changing to a frame that is traveling at the speed of ... of ...

...light, because you're solving the wave equation for light. The solution is a light wave moving with the speed of light "c".