Solving 0.2uf & 0.1uf Capacitance Connected in Series to a 9V Battery

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SUMMARY

The discussion focuses on calculating the potential difference and charge across a 0.2µF and a 0.1µF capacitor connected in series to a 9V battery. The total capacitance for capacitors in series is determined using the formula 1/C_total = 1/C1 + 1/C2, resulting in a total capacitance of 0.0667µF. The potential difference across each capacitor can be calculated using the voltage divider rule, and the charge on each capacitor is the same due to the series connection, calculated as Q = C_total * V.

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Homework Statement


A 0.2uf and 0.1uf capacitor are connected in series to a 9V battery. Calculate a) the potential difference across each capacitor and b) the charge on each.


Homework Equations


Not sure


The Attempt at a Solution


I don't even know where to begin, sorry :(
 
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anyone? please help sort of urgent
 

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