Solving 3((e^x)-1)-xe^x=0 Equation

  • Thread starter Thread starter hamamo
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around solving the equation 3((e^x)-1)-xe^x=0, which involves exponential functions. Participants are exploring methods to find solutions, including graphical approaches and the use of the Lambert W function.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest that the equation cannot be solved algebraically and can only be approximated. Others propose using graphical methods to identify solutions. The Lambert W function is mentioned as a potential tool for solving the equation, with requests for more information on its application.

Discussion Status

Participants are actively sharing insights and methods, with some expressing uncertainty about the existence of multiple solutions. There is a recognition of a known solution at x=0, and further exploration of additional solutions is ongoing. Guidance on using the Lambert W function and iterative methods has been provided, contributing to the discussion.

Contextual Notes

One participant notes that the equation is derived from the context of black body radiation and Wien's displacement law, indicating a specific application for the solution sought.

hamamo
Messages
14
Reaction score
0
hi there;
please can anyone help me solving this
3((e^x)-1)-xe^x=0
sorry i couldn't use more elegant form to write the equation
i use some software and they help
but i can't do it in hand
 
Physics news on Phys.org
hamamo said:
hi there;
please can anyone help me solving this
3((e^x)-1)-xe^x=0
sorry i couldn't use more elegant form to write the equation
i use some software and they help
but i can't do it in hand

3(e^{x}-1)-xe^{x}=0 I do not believe you can solve this one algebraically, one can only approximate the solution to these kind of equations.
 
i think a graphical method is usefull...

ciao
 

Attachments

  • equations.jpg
    equations.jpg
    35.1 KB · Views: 411
thanx for the reply up there
but i search more and i found this kind of equation can be solved using
Lambart w-function
or omega function, the problem i couldn't have more information about this function else some expansion series and i can't even write a code to solve or to find a value in lambart function
any more help will be useful
thanx
 
sutupidmath said:
3(e^{x}-1)-xe^{x}=0 I do not believe you can solve this one algebraically, one can only approximate the solution to these kind of equations.

can you help me using the latex
 
By inspection we can see x=0 is a solution. Do you have any reasoning to believe there are other solutions?

Edit = maybe I was to hasty - there seems that there is at least one more solution.
 
Last edited:
sutupidmath said:
3(e^{x}-1)-xe^{x}=0 I do not believe you can solve this one algebraically, one can only approximate the solution to these kind of equations.

hamamo said:
can you help me using the latex
If you click on the formula, you will see the code in a new window.
 
tanx for the reply
the 0 solution i know about it
and there is another solution if you graph the equation you can find it approximately
its about 2.something
 
by the way
this equation is a result for the Blanck's low and Wien's displacement low
i want to calculate the Wien's constant at the maximum wave length of black body radiation
so
i differentiate Blanck's low and solve the equation for which x have a maximum value
and the result is something like this equation
which now i need to solve for x to find max and min value
 
  • #10
hamamo said:
thanx for the reply up there
but i search more and i found this kind of equation can be solved using
Lambart w-function
or omega function, the problem i couldn't have more information about this function else some expansion series and i can't even write a code to solve or to find a value in lambart function
any more help will be useful
thanx

Hello Hamamo, if you want some code to calculate the Lambert W function, you might consider using the definition of it and the method of Newton-Raphson. The definition as you might know is:

X=Ye^Y \qquad \rightarrow \qquad Y=W(X)

Thus if you define a function f as:

f=Ye^Y-X

You can use the method of Newton Raphson to be for calculating this function:

Y_{n+1}=Y_n-\frac{Y_ne^{Y_n}-X}{e^{Y_n}(Y_n+1)}

Or:

Y_{n+1}=\frac{e^{Y_n}Y_n^2+X}{e^{Y_n}(Y_n+1)}

Take 0 as start value and use this iterative scheme to calculate the solution as the resulting value of the Lambert W function. It converges extremely fast. 5 iterations for the value of the function you are looking to solve.

best regards, Coomast

[Edit] The results of the iteration if you use it on your function:
step n Yn Yn+1
1 0 -0.149361
2 -0.149361 -0.177647
3 -0.177647 -0.178560
4 -0.178560 -0.178561
5 -0.178561 -0.178561

Which is x-3, thus x=2.821439 is the one you need
 
Last edited:
  • #11
thanx coomast
you r helpfull that's what i need
thanx again
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
7
Views
2K
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
4
Views
2K
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K