Solving a Carnot Engine Problem: What Unit Do I Use?

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Homework Help Overview

The discussion revolves around a problem related to the efficiency of a Carnot engine and the appropriate units for temperature in thermodynamic calculations. The original poster is attempting to determine how much to increase the temperature of the high-temperature reservoir to achieve a specified efficiency.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of different temperature units, including Kelvin and Celsius, and question the appropriateness of these units in the context of thermodynamics. There is also mention of various other units that could be relevant to the problem.

Discussion Status

Some participants have provided guidance on the necessity of using Kelvin for temperature in thermodynamic calculations, while others express confusion about the initial attempts and results. Multiple interpretations of the problem and unit choices are being explored.

Contextual Notes

There is a noted constraint regarding the requirement to use Kelvin in thermodynamics, which some participants are questioning based on their initial calculations. The original poster has expressed uncertainty about the correctness of their numerical answer and the units used.

sophzilla
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I solved the problem, but I can't get the right unit for the answer.

A Carnot engine whose low-temperature reservoir is at 16°C has an efficiency of 31%. By how much should the temperature of the high-temperature reservoir be increased to increase the efficiency to 70%?

My numerical answer is 544.8. I tried Kelvin first - the most obvious choice - but that was wrong. Then I tried celsius and J/K.

I tried to work it out but I have no earthly idea - the other choices include:
- C0 (like the celsius sign but the circle is after the C)
-J/kg*K
-J/mol*K and
-kJ/kg

Any help would be grately appreciated.
 
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sophzilla said:
My numerical answer is 544.8. I tried Kelvin first - the most obvious choice - but that was wrong. Then I tried celsius and J/K.

I tried to work it out but I have no earthly idea - the other choices include:
- C0 (like the celsius sign but the circle is after the C)
-J/kg*K
-J/mol*K and
-kJ/kg

Any help would be grately appreciated.
You have to use Kelvin for temperature in thermodynamics. I get 544.5 K as the increase (from 418.8 K to 963.33 K)

AM
 
Well...the thing is, I did use Kelvin. That was my first choice, but it was wrong. Any other sound possibilities?
 
sophzilla said:
Well...the thing is, I did use Kelvin. That was my first choice, but it was wrong. Any other sound possibilities?
Mind you, this temperature difference is also 544.5 degrees Celsius. It is just that you have to work out the thermodynamics part in K and then convert back to Celsius.

AM
 

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