Solving a Carnot Engine Question: Power Output and Wasted Energy Calculation

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The discussion centers on calculating the power output and wasted energy of a Carnot engine operating between 80°C and 350°C, absorbing 21,000 J of energy per cycle. The ideal Carnot efficiency is calculated as 0.7714, leading to the determination of mechanical power output using the formula: power out equals efficiency multiplied by power in. For the wasted energy, the calculation involves subtracting the power output from the power input. There is clarification on terminology, emphasizing that "power in" should refer to the net rate of heat transfer into the system, while noting that "power in" is not a strictly defined term. The conversation highlights the importance of understanding energy balance in closed systems for accurate calculations.
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Homework Statement



A heat engine operates in a Carnot cycle between 80 degrees C and 350 degrees C. It absorbs 21,000 J of energy per cycle from the hot reservoir. a. THe duration of each cycle is 1s. What is the mechanical power output of the engine? b. How much energy does it expel in each cycle by heat?



The Attempt at a Solution



Part A

Ideal Carnot Efficiency= 1- Tc/Th= .7714

Power out=efficiency*power in

Part B

Wasted Energy=power in-power out


Is that the correct strategy to solve this problem?
 
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It sounds to me like the question is asking (in part b) for the Heat Transfer out of the system in which case you mat want to consider writing out the Energy Balance for a closed system.

For part (a) if by "power in" you mean the net rate of heat transfer into the system, then yes, that is correct.

But, strictly speaking, there is no "power in".
 
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