Solving a Charge at the Center of a Sphere Problem

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SUMMARY

The problem involves determining the electric field generated by a positive charge q placed at the center of a hollow conducting sphere with inner radius R1 (9 cm) and outer radius R2 (10 cm). Using Gauss' law, the electric field for regions outside the sphere (r > R2) is expressed as E = q / (4 π ε₀ r²). The discussion highlights the importance of recognizing three distinct regions: r < R1, R1 < r < R2, and r > R2, which leads to different electric field expressions for each region. The user initially overlooked the significance of the radii but gained clarity on the necessity of addressing all regions to fully solve the problem.

PREREQUISITES
  • Understanding of Gauss' law in electrostatics
  • Knowledge of electric fields and charge distributions
  • Familiarity with spherical coordinates and symmetry in physics
  • Basic algebra for manipulating equations involving electric fields
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  • Study the application of Gauss' law in different geometries, focusing on spherical symmetry
  • Learn about electric field calculations in regions with different charge distributions
  • Explore the concept of induced charge on conductors and its implications
  • Investigate the behavior of electric fields in multiple regions surrounding charged objects
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Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric fields and Gauss' law applications in spherical geometries.

BOAS
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Homework Statement



A positive charge q is placed at the center of a hollow electrically neutral conducting sphere (inner radius R1 9cm, outer radius R2 10 cm.

Using Gauss' law determine the electric field of every point in space, as a function of r (the distance from the center of the sphere). Only the algebraic expression is required.

Homework Equations

The Attempt at a Solution



I'm unsure of how to go about this problem, all the examples I have seen discuss thin spheres.

A positive charge at the center of the sphere would induce a positive charge on the surface of the sphere, whilst a negative one would be induced on the inner surface.

I think it is safe to assume the charge at the center is a point and therefore the charge will be evenly distributed creating a symmetrical electric field.

\Phi _{0} = ( \Sigma \cos \phi) \Delta A

I know I need to 'construct' a gaussian surface with radius r (r>R2) concentric with the shell, but I don't know how to use the information about the two radii I was given - Are they important here?

Since the electric field is everywhere perpendicular to the gaussian surface, \phi = 0^{o} and \cos \phi = 1.

The electric charge has the same value all over the surface, so we can say that;

\Phi _{0} = E( \Sigma \Delta A) = E(4 \pi r^{2})

Setting \Phi _{0} = \frac{q}{\epsilon _{0}}

We can say that E = \frac{q}{4 \pi \epsilon _{0} r^{2}}

For r > R2 since Gauss' law also shows us that there is no net charge inside the sphere.

The above makes sense to me, but at no point did I use the radii given to me in the question...

What am I doing wrong?

Thanks!

BOAS
 
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BOAS said:
I know I need to 'construct' a gaussian surface with radius r (r>R2) concentric with the shell, but I don't know how to use the information about the two radii I was given - Are they important here?
They are important because they mark off three distinct regions: r < R1; R1 < r < R2; r > R2.

You only dealt with the last region. What about the others?
 
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Ok, that was surprisingly obvious.

I'll have three distinct expressions, does that satisfy the question of finding the electric field of every point in space?

I suppose that it does, but on first reading of the question I was expecting a single expression.

Thanks for your help, I'm confident I can do this now.
 

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