Solving a circuit using Kirchhoff's Rules

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SUMMARY

This discussion focuses on solving electrical circuits using Kirchhoff's Rules, specifically addressing the calculation of current and voltage drops across resistors in a circuit. The participant initially calculated a total voltage of 25V and determined the total resistance to be 10 ohms, leading to a current of 2.5 amps through resistor R1, with subsequent calculations for resistors R2 and R3. However, confusion arose regarding the correct setup of the circuit, particularly in identifying the configuration of resistors and voltage sources. The discussion emphasizes the importance of advanced techniques such as mesh currents and nodal analysis for complex circuits.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL)
  • Familiarity with series and parallel resistor configurations
  • Basic knowledge of Ohm's Law (V=IR)
  • Experience with circuit analysis techniques, including mesh and nodal analysis
NEXT STEPS
  • Study mesh current analysis for solving complex circuits
  • Learn nodal analysis techniques for circuit voltage and current calculations
  • Explore advanced circuit simulation tools like LTspice or Multisim
  • Review examples of wye and delta resistor configurations in circuit design
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of circuit analysis using Kirchhoff's Rules.

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Homework Statement



using kirchhoff's rules, determine the current through and voltage drop across each resistor in the accompanying figure.
circuit.jpg



Homework Equations


V=IR, potential voltage ( voltage drop )= current * resistance
Voltage in series Vt=V1 + V2 + V3...
Current in series It = I1 = I2 = I3...
Resistance in series Rt= R1 + R2 + R3...

Voltage in parallel Vt= V1 + V2 + V3..
Current in parallel It = I1+ I2 + I3..
Resistance in parallel 1/Rt= 1/R1 + 1/R2...

these are the equations we've been using in class

The Attempt at a Solution



i wasnt sure how to start this problem since i don't have any similar examples to look at. but what i did was add the two voltages of the batteries to get a total of 25 V. i also assumed that resistors 2 and 3 were in parallel, and together were in series with resistor 1. making the total resistance 10. ( 1/6 + 1/3 = 3/6 ; 1/(3/6) = 2 ; 8+2 = 10) so that gave me a current of 2.5. so i got the current through R1 to be 2.5 amps, thecurrent through R2 to be .833 and the current through R3 to be 1.67.
the voltage drop across R1 to be 20 V (2.5 amp * 8 ohms), across R2 to be 5 and across R3 to be 5

im pretty sure i didnt do it right but I am not sure how i should set up the problem. in class our teacher gave us an example like this one with two batteries. but i got confused when he was drawing the arrows for the direction of the current. he drew current flowing from A to B, but also from B to A. i tried to figure it out doing that but it seems too complicated. i always end up with current flowing into a battery through the wrong end. can someone please show me how to set it up correctly? thanks
 

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When solving a circuit problem you really only have two ways of solving it: KVL or KCL.

The voltage sources are NOT in parallel neither are resistors 2 and 3. This is a wye bridge I believe.
 
Alright, when provided with college-level circuits, it's time to take a college-level approach to solving circuit problems. The good old method of adding voltages and resistances together just doesn't work well anymore. While the approach of separating the "batteries" from the "load" works with simple configurations, they quickly become non-applicable to complex circuits.

Have you been taught about mesh currents or nodal analysis?
 

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