Solving a Collar's Angular Momentum Problem: Finding f(θ) and Max θ Reached

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving a collar's angular momentum, specifically finding the function \dot\theta=f(\theta) and determining the maximum angle \theta reached. The context includes forces acting on the collar and considerations regarding non-inertial frames of reference.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the collar, including gravitational force, normal force, and an external force. There are attempts to relate these forces to the angle \theta and the collar's motion. Questions arise about the necessity of using non-inertial frames and how to express the forces in terms of the angle.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem setup. Some have provided insights into the forces involved and the implications of the collar's initial position. There is recognition of the complexities introduced by the frame's acceleration, and participants are encouraged to share their equations and reasoning, regardless of their completeness.

Contextual Notes

There is a noted ambiguity regarding the collar's initial position and the direction of the forces acting on it. Participants are also considering the implications of the frame's acceleration on the forces experienced by the collar.

harmyder
Messages
33
Reaction score
1

Homework Statement


Initially collar is at rest with theta = 0. Find [tex]\dot\theta=f(\theta).[/tex] And find maximum theta reached.

upload_2016-2-16_11-14-0.png


Homework Equations


I don't know if i allowed to use angular momentum about top-right frame corner as it's accelerating.

But i definitely will need second Newton law:)

The Attempt at a Solution


I know that there mg, N forces. But i can't figure out another force due to acceleration of the frame.
 
Physics news on Phys.org
Are you comfortable using non-inertial frames of reference?
 
haruspex said:
Are you comfortable using non-inertial frames of reference?

I think I'm not, but i believe there is no need in it here. Important thing is that i need to calculate θ' based on θ not on t.
 
harmyder said:
I think I'm not, but i believe there is no need in it here. Important thing is that i need to calculate θ' based on θ not on t.
It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.
 
  • Like
Likes   Reactions: harmyder
haruspex said:
It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.

The collar undergoes three forces - [itex]m\mathbf{g}, \mathbf{N}, \mathbf{F}_{ext}[/itex]. From which [itex]|m\mathbf{g}|=|N|[/itex], though i can't prove it.

With angle [itex]\theta[/itex] we have:
[itex]|m\mathbf{g}|[/itex] acting downward and [itex]\big(|\mathbf{N}| + |\mathbf{F}_{ext}|\big)\cos\theta[/itex] acting upward.

The maximum angle is reached with equilibrium.

And here i can't calculate the external force.
 
harmyder said:
The collar undergoes three forces - [itex]m\mathbf{g}, \mathbf{N}, \mathbf{F}_{ext}[/itex]. From which [itex]|m\mathbf{g}|=|N|[/itex], though i can't prove it.

With angle [itex]\theta[/itex] we have:
[itex]|m\mathbf{g}|[/itex] acting downward and [itex]\big(|\mathbf{N}| + |\mathbf{F}_{ext}|\big)\cos\theta[/itex] acting upward.

The maximum angle is reached with equilibrium.

And here i can't calculate the external force.
The external force acts on the frame, not on the collar.
Why do you think |mg|=|N|? Consider horizontal and vertical separately.
 
haruspex said:
It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.

I can't come up with solution in [itex]\hat{i}\times\hat{j}[/itex] frame.
sliding_collar.png

Maybe i need to consider tangential parts of [itex]mg[/itex] and anther force, i think this another force is [itex]ma[/itex]? When they become equal, then no more change of angle.
 
The original post said "Initially collar is at rest with theta = 0" and according to the picture "theta= 0" is at the bottom! The collar won't move- [itex]\theta'= 0[/itex]. If you intended to the initial point to be at the top, with "theta" measured from the top, then, at each [itex]\theta[/itex], the downward acceleration vector, <0, -g>, can be written as the sum of two vectors, one parallel to the normal vector circular bar and one parallel to the tangent vector. Since the collar can't move normal to the bar, only the tangent vector is relevant.
 
HallsofIvy said:
The original post said "Initially collar is at rest with theta = 0" and according to the picture "theta= 0" is at the bottom! The collar won't move- [itex]\theta'= 0[/itex].
Have you noticed rightward horizontal acceleration of the frame?
 
  • #10
harmyder said:
Maybe i need to consider tangential parts of [itex]mg[/itex] and anther force, i think this another force is [itex]ma[/itex]? When they become equal, then no more change of angle.
That is the non-inertial frame method I mentioned. You treat the acceleration as a 'fictitious' force ma acting the other way.
So what answer do you get?
 
  • #11
harmyder said:
Have you noticed rightward horizontal acceleration of the frame?
NO! I hadn't. Thanks.
 

Similar threads

Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
26
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
335
Views
17K
  • · Replies 32 ·
2
Replies
32
Views
3K