- #1

Duderonimous

- 63

- 1

## Homework Statement

Find all solutions. Solve explicitly for y.

y[itex]^{'}[/itex]=y[itex]^{2}[/itex]-y

## Homework Equations

## The Attempt at a Solution

Case where y'=0

0=y(y-1) y=0,1 when y(t)=0

Case where y'[itex]\neq[/itex]0

y'=y[itex]^{2}[/itex]-y

[itex]\frac{1}{y^{2}-y}[/itex]y'=1

[itex]\int\frac{1}{y^{2}-y}[/itex]y'dt=∫1dt

[itex]\int\frac{1}{y^{2}-y}[/itex]dy=t+c

Cant figure our where to go from here.

Last edited: