1. The problem statement, all variables and given/known data Solve the initial value problem: t(dy/dt)+8y=t^3 where t>0 and y(1)=0 2. Relevant equations None? 3. The attempt at a solution It's a linear equation, so rearranged to dy/dt+8y/t=t^2. Took the integrating factor e^(∫8/tdt)=t^8 and multiplied through. (t^8)dy/dt+8t^7y=t^10. ∫(t^8y)'dt=∫t^10dt t^8y=(t^11)/11 + C Solve for C, I got -1/11. Final solution is y=(t^3)/11 - 1/(11t^8) This isn't right, though. Does anyone see where I made the mistake? Thanks!