Solving a Heat/Energy Problem: Final Temp of Steam

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Homework Help Overview

The discussion revolves around a heat and energy problem involving the calculation of the final temperature of steam after adding a specific amount of heat to water at an initial temperature. The subject area includes thermodynamics, specifically the concepts of specific heat, latent heat of fusion, and latent heat of vaporization.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the original poster's approach to the problem, questioning the application of latent heat of fusion and the initial state of the water. There are suggestions to reconsider the energy balance and the stages of heating and phase change.

Discussion Status

The discussion is active, with participants providing guidance on how to approach the problem. There is an emphasis on understanding the physics involved and the need to derive the correct expression for energy changes at different stages of the process. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants note potential confusion regarding the initial state of the water and the implications of adding heat, as well as the need to clarify the role of latent heat in the calculations. The original poster's calculations are questioned, and there is a focus on ensuring that all relevant factors are considered in the energy balance.

PHYclueless
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Hello all. I have two questions I need help with but I'll post them in separate posts. I'll attach the problem and the work I've attempted. If someone could give me another idea I'd appreciate it. Thank you!

To make steam, you add 5.6x10^5J of heat to .220kg of water at an initial temperature of 50c. Find the final temperature of the steam, assuming a specific heat for steam = 2010J/(kg K), latent heat of fusion for water=33.5x10^4J/kg, and a latent heat of vaporization =22.6x10^5J/kg.

This is what I started working on and my answer comes out to be 38 degrees but the true answer is 138. Not sure where I'm going wrong here.

mass(specific heat)(change in temp)+mass(latent fusion)+mass(specific heat)(Tf-Ti)+mass(latent vaporization)=Energy

.220kg(4186J/kgc)(50c)+.220kg(33.5x10^4J/kg)+.220kg(4186J/kgc)(Tf-100c)+.220kg(22.6x10^5)=5.6x10^5J

Thanks!
 
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That's because you "melted" your 50 degree (hot) water.
 
PHYclueless said:
Hello all. I have two questions I need help with but I'll post them in separate posts. I'll attach the problem and the work I've attempted. If someone could give me another idea I'd appreciate it. Thank you!

To make steam, you add 5.6x10^5J of heat to .220kg of water at an initial temperature of 50c. Find the final temperature of the steam, assuming a specific heat for steam = 2010J/(kg K), latent heat of fusion for water=33.5x10^4J/kg, and a latent heat of vaporization =22.6x10^5J/kg.

This is what I started working on and my answer comes out to be 38 degrees but the true answer is 138. Not sure where I'm going wrong here.

mass(specific heat)(change in temp)+mass(latent fusion)+mass(specific heat)(Tf-Ti)+mass(latent vaporization)=Energy

.220kg(4186J/kgc)(50c)+.220kg(33.5x10^4J/kg)+.220kg(4186J/kgc)(Tf-100c)+.220kg(22.6x10^5)=5.6x10^5J
What does the latent heat of fusion have to do with this problem? What state is the water in initially? What happens when heat is added?

You have to apply your knowledge of physics to derive the correct expression first and be able to explain it.

I suggest you work out the equation for temperature change and then plug in the numbers.

AM
 
Do you really think the water will become cooler if you add heat to it? I suggest you first determine, using the specific heat, if the energy added will be enough to make it vaporize. If so, determine how much energy is left over for when you change from 50-100 degrees. Then determine if all the water will vaporize with the left-over energy there. From there you can use another specific heat to determine how much the steam heats up. Remember that your equation will change at every stage since the specific heats will change. 1 equation will not solve this.
 

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