Solving a Matrix: Finding Positive & Negative Solutions

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SUMMARY

The discussion focuses on solving a system of linear equations represented by a matrix, specifically the equations X1 + X2 + X3 + X4 = 0, X1 + X2 - X3 - X4 = 0, and X1 - X2 + X3 - X4 = 0. The solutions are expressed in terms of a free variable 't', resulting in X1 = t, X2 = -t, X3 = -t, and X4 = t. The signs of the variables are determined by the requirement that their sums equal zero in each equation, demonstrating the relationship between the variables and their respective signs.

PREREQUISITES
  • Understanding of linear algebra concepts, particularly systems of equations.
  • Familiarity with matrix representation of equations.
  • Knowledge of free variables in linear systems.
  • Basic skills in substitution methods for solving equations.
NEXT STEPS
  • Study the concept of free variables in linear algebra.
  • Learn about matrix row reduction techniques for solving systems of equations.
  • Explore the implications of variable signs in linear equations.
  • Practice solving similar systems of equations with different parameters.
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Students of linear algebra, educators teaching systems of equations, and anyone looking to deepen their understanding of matrix solutions and variable relationships.

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have a matrix:

X1+X2+X3+X4 = 0
X1+X2-X3-X4 = 0
X1-X2+X3-X4 = 0

the solutions that are formed are:
t
-t
-t
t

Now i understand that they just used t to label the free variables.. but Iam not sure how they were able to tell which were negative and positive.. I tried to do it out, but just confused myself more.. Help anyone?
 
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The answer means:
X1 = t
X2 = -t
X3 = -t
X4 = t

The reason for the signs is they have to add to zero in all three cases.

For instance:
Take X1+X2+X3+X4

If you substitute the answer in you get:

t+ (-t) + (-t)+t

t+(-t) is zero and (-t)+t is zero so they add to zero.

In the second case:

X1+X2-X3-X4

In this case substituting in the answer:

t + (-t) - (-t) - t

t + (-t) is zero and -(-t)-t is zero

The third case is left as an exercise for the student.
 

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