Solving a Moment Equation: Understanding the Relationship with AD

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SUMMARY

The discussion centers on solving a moment equation involving vectors and their relationships in a system at equilibrium. The equation presented is u · (rB x tB + rE x W) = 0, where rB and rE are position vectors, tB is tension, and W is a force. Participants clarify that the moment of the forces at point A about D is not included in the dot product with vector u because it is orthogonal, thus simplifying the equation. The key takeaway is understanding how to manipulate vector equations to isolate unknowns while maintaining equilibrium conditions.

PREREQUISITES
  • Vector calculus, specifically cross and dot products
  • Understanding of equilibrium conditions in mechanics
  • Familiarity with moment equations in physics
  • Knowledge of vector notation and operations
NEXT STEPS
  • Study the principles of static equilibrium in mechanics
  • Learn about vector cross products and their geometric interpretations
  • Explore the application of dot products in physics problems
  • Investigate the role of tension and forces in moment calculations
USEFUL FOR

Students and professionals in physics, engineering, and mechanics who are working on problems involving equilibrium and vector analysis will benefit from this discussion.

  • #31
goldfish9776 said:
because when rE x W and rb xTB are not perpendicular to u , then i can't say that u . (rE x W) and u .(rb xTB ) = 0
Nobody is saying those two dot products are individually zero.
The balance of torques gives us that rE x W + rb x TB + rDA x force_at_A = 0.
We take the dot product of that with u to obtain the equation u.(rE x W) + u.(rb x TB) + u.(rDA x force_at_A) = 0.
We then observe that since u is parallel to rDA the triple product u.(rDA x force_at_A) must be zero.
From that we conclude u.(rE x W) + u.(rb x TB) = 0.
This does not tell us anything about whether u is parallel to any of the four other vectors in that equation.
 

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