Solving a Partially Decoupled System with Initial Values

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SUMMARY

The discussion focuses on solving a system of differential equations defined by dx/dt = 2x - 3y² and dy/dt = -3y, with initial conditions x(0) = 0 and y(0) = 1. The solution for y(t) is derived as y(t) = c1e^(-3t). The next step involves solving the linear inhomogeneous first-order differential equation for x(t) using the integrating factor e^(-2t) to simplify the equation to d/dt(e^(-2t)x) = -3e^(-2t)(c1e^(-3t))², which can be integrated to find x(t).

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Homework Statement

dx/dt = 2x - 3y2
dy/dt = -3y

Derive the general solution and find the solution that satisfies the initial values: x(0) = 0 and y(0) = 1.

The attempt at a solution

dy/dt = -3y
y(t) = c1e-3t

dx/dt = 2x - 3(c1e-3t)2

I have no idea where to go from here. Any help?
 
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The equation ##\frac{dx}{dt}-2x=-3(c_{1}e^{-3t})^{2}## is just a linear, inhomogenous 1st order DE. The method of solving it is multiplying both sides of the eq with the integrating factor ##e^{-2t}## and using the "derivative of product" rule to get ##\frac{d}{dt}(e^{-2t}x)=-3e^{-2t}(c_{1}e^{-3t})^{2}##. This equation can be directly integrated to find the function x(t).
 

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