Solving a Suspended Ball in an Electric Field

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Homework Help Overview

The problem involves a ball suspended in a uniform electric field, with specific parameters including mass and charge. The objective is to determine the electric field strength based on the forces acting on the ball.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of a triangle method to visualize forces acting on the ball and question the correctness of the triangle drawn. There is an emphasis on the equilibrium condition of the forces and the direction of the tension force.

Discussion Status

Some participants have provided guidance on the importance of correctly identifying the direction of forces in the triangle method. There is acknowledgment of a mistake in the tension force direction, which has led to improved understanding. However, the calculation of the electric field strength is mentioned without further exploration of its implications.

Contextual Notes

Participants are operating under the assumption that the ball is in equilibrium, which is central to their reasoning about the forces involved. There is a focus on the relationship between the electric field and the forces acting on the ball.

Jabababa
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Homework Statement



a 030 kg ball is suspended in a uniform electric field as shown. If the charge on the ball is 500 x10^-4 C, what is the electric field strength?

Homework Equations



E= F/Q

The Attempt at a Solution



I did this by using the triangle method. draw the forces with a triangle(look at the attachment).
My question is did i draw the triangle right? Does the direction of the Electric field affect my answer?
 

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My question is did i draw the triangle right?
Since the ball is in equilibrium, the forces on it must add to zero.
Look at the direction of the tension force in your triangle.
 
oh my, thank you so much ap123!

I just got the tension force backwards, now it makes much more sense! thank you !
 
Have you worked out the value for the electric field?
 
yes i got 1.25 x10^3 N/C to the left
 

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