Solving a system with the inverse of a matrix.

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Homework Help Overview

The discussion revolves around solving a system of equations using the inverse of a matrix, specifically focusing on the application of Gauss-Jordan elimination to find the inverse of a given matrix and subsequently using that inverse to solve a system of linear equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the matrix from part a) and the system of equations in part b). There is confusion regarding how the inverse of one matrix can be applied to solve for another. Some participants suggest reformulating the system into a matrix equation format.

Discussion Status

The discussion is ongoing, with some participants expressing uncertainty about the connection between the two parts of the problem. A participant has identified a potential error in the problem statement, which may clarify the situation moving forward.

Contextual Notes

There is mention of a possible mistake in the original problem setup, as one participant has contacted their TA and received confirmation of an error in the equations provided for part b).

thatguythere
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Homework Statement


a)Use Gauss-Jordan elimination to find the inverse of A =
[ 2 1 4 ]
[ 1 1 2 ]
[ -2 -3 -2 ]

b) Use the result from part a) to find the solution of the following system.

5x+2y-3z = 5
x+y-z = -1
-3x-y+2z = 2

Homework Equations





The Attempt at a Solution



My problem is not with part a), I quite easily found the inverse of the matrix. What I am not understanding is what exactly they are asking me to do for part b). How can I use the inverse of one matrix to solve for another? Any help is greatly appreciated.
 
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If you change

5x+2y-3z = 5
x+y-z = -1
-3x-y+2z = 2

into a matrix equation in the form of Bx=C, what would B, X and C be?
 
rock.freak667 said:
If you change

5x+2y-3z = 5
x+y-z = -1
-3x-y+2z = 2

into a matrix equation in the form of Bx=C, what would B, X and C be?

I'm with thatguythere. I can't see that the matrix in part b) is related in any simple way to the matrix in part a). I'm suspecting the somebody goofed when assembling the problem.
 
I contacted my TA and it is indeed a mistake. It should be
2x + y + 4z = 5
x + y + 2z = -1
-2x -3y -2z = 2
I should be able to manage now, thanks.
 
Dick said:
I'm with thatguythere. I can't see that the matrix in part b) is related in any simple way to the matrix in part a). I'm suspecting the somebody goofed when assembling the problem.

Ah well, I didn't calculate the inverse, so I assumed it one of those problems where the matrix equation would be A-1x=B
 

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