Solving a Vector Problem: Find Magnitude & Direction

AI Thread Summary
The discussion revolves around solving a vector problem involving two displacements of a mop. The first displacement is 110 cm at an angle of 110°, and the resultant displacement is 240 cm at 25°. The participant initially struggled with calculating the second displacement and mistakenly measured angles incorrectly. After some guidance, they realized the importance of considering negative values in their calculations, which led to finding the correct answer. The conversation highlights the significance of accurately interpreting angles and vector components in solving physics problems.
Dreams2Knight
Messages
8
Reaction score
0
[SOLVED] Vector Problem

I hope someone can help me. I am so tired of trying to figure this out.

A man pushing a mop across a floor causes the map to undergo two displacements. The first has a magnitude of 110 cm and makes an angle of 110° with the positive x axis. The resultant displacement has a magnitude of 240 cm and is directed at an angle of 25.0° to the positive x axis. Find the magnitude and direction of the second displacement. Find the angle with respect to the positive x axis.

I started by measuring 110 degrees and drew my vector starting at the origin (origin is point A). The end of this first vector is point C. Then, starting at point A again (since this vector is the resultant vector) I measured an angle of 155 degrees (180-25=155) and drew my vector, the end of which is labeled point B. I then drew the connecting vector, vector BC.

Now, I drew a line straight down from point B to the x-axis. This point is D. I need to find the x and y components of this right triangle, triangle ABD. By using the angle of 155 degrees I can say cos155=x divided by 240. This equals -217.5139. To find y, I can say sin155=y divided by 240. This is 101.4284.

Now, I drew a line from point C straight over to the y-axis. This will be point E. I need to find the components of triangle ACE. So, cos110=x divided by 110. This is -37.6222. And sin110=y divided by 110. This is 103.3662.

This is the point where I'm not sure what to do. Since the unknown vector, BC, is a hypotenuse of a third right triangle, I just don't know what to do next. I thought I could take the difference of the x values and y values I found, then use the Pythagorean theorem to get vector BC, but I get the wrong answer. (I keep getting vector BC equals 180.)

I hope I was able to explain what I did without confusing anyone. I would be ever so grateful for some help.
 
Physics news on Phys.org
I measured an angle of 155 degrees (180-25=155) and drew my vector

I don't understand what you're doing here. Why not draw it at 25 degrees? That's the direction it's supposed to point, as stated in the problem. Maybe I'm just not picturing what you did.

I haven't gone through your entire solution since I don't get what you did above, but I don't think you need to worry about finding the components of anything here. If you draw the two vectors given you can easily find the magnitude and direction of the "second displacement" by the cosine law and the sine law.

Hope that helps.
 
hage567 said:
I don't understand what you're doing here. Why not draw it at 25 degrees? That's the direction it's supposed to point, as stated in the problem. Maybe I'm just not picturing what you did.

Oh my god, I don't know why I thought the 25 degrees had to measured from the 180 degree line! :redface: My mind is so confused, I guess I just got it turned around with another problem I was doing. Some of the other problems I'm doing do give you the angle from the 180 degree line.

I"m going to rework the problem. I'll post my results.
 
Urgh. I'm STILL getting the same answer. I've done all I can do tonight. I've got to sleep. I'll work on this again tomorrow.
 
Hi Dreams2Knight,

Your procedure of subtracting the x and y values to give the x and y components of BC, and then using the Pythagorean theorem, sounds like the right thing to do. What numbers did you use and get?

It's difficult to follow without knowing the numbers that you actually plugged in, but perhaps you made an error in subtracting the x values? If you did not take into account that one of the x values was negative, the mistake would lead to a final answer of about 180.
 
alphysicist said:
Hi Dreams2Knight,

If you did not take into account that one of the x values was negative, the mistake would lead to a final answer of about 180.

Ah, well that was the problem. I didn't use the negative. I now have the correct answer! Something so simple caused me so much grief. Thank you for bringing that to my attention. I sure appreciate the help.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top