Solving Airplane Pilot Problem - Find Angle & Speed Over Ground

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SUMMARY

The discussion focuses on solving the Airplane Pilot Problem, where a pilot aims to fly due west against a southward wind of 88.0 mph while maintaining an airspeed of 375 mph. The solution involves using trigonometric principles to determine the necessary heading angle and the resultant ground speed. Specifically, the Y component of the plane's velocity must counteract the wind, forming a right triangle where the hypotenuse represents the airspeed. The Pythagorean theorem is essential for calculating the angle and speed over ground.

PREREQUISITES
  • Understanding of basic trigonometry and right triangles
  • Familiarity with the Pythagorean theorem
  • Knowledge of vector components in physics
  • Basic principles of flight dynamics
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  • Study vector addition in physics to understand how to combine velocities
  • Learn about trigonometric functions and their applications in navigation
  • Explore the concept of airspeed versus ground speed in aviation
  • Practice solving similar problems involving wind effects on flight paths
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Aerospace engineers, flight instructors, pilots, and students studying physics or aviation who need to understand the impact of wind on flight navigation.

clair_a_net
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oh I am having a problem trying to solve the following problem.

An airplane pilot wishes to fly due west. A wind of 88.0 is blowing toward the south.

with :If the airspeed of the plane (its speed in still air) is 375 , in which direction should the pilot head?

can't figure out how to solve for the angle. any pointers?


and to find the :What is the speed of the plane over the ground?


this part should be easier once i have the angle. i think

thanks
clair_a_net
 
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Think of it like a triangle.

Since the pilot wishes to fly due west, it must counteract the south wind with the Y component of the plane's velocity due north of equal magnitude. So one leg of the triangle is 88 mph north, or posotive Y if its easier to think that way.

The hypotenuse(sp?) must be 375 because that's how fast the plane is going, and the bottom leg of the triangle is the speed as it appears to be moving due west, or the X component of the velocity.

Using the pathagreon(sp?) theorum and some trig, the numbers should pop out no problem.
 

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