Solving an Electric Field Due to an Infinite Cylinder

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Homework Help Overview

The problem involves calculating the electric field produced by an infinitely long cylinder with a uniform volume charge density. The specific parameters include a cylinder radius of 4.0 cm and a charge density of 200 nC/m³, with the electric field being evaluated at a distance of 8.0 cm from the center.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Gauss's Law and the symmetry of the problem. There are attempts to convert volume charge density to linear charge density and calculate the electric field using different approaches. Some participants express confusion regarding the calculations and the correct application of formulas.

Discussion Status

The discussion is active, with participants exploring various methods to solve the problem. Some guidance has been offered regarding the use of Gauss's Law and the appropriate geometric considerations for the cylinder. There is no explicit consensus on the correct approach yet, as multiple interpretations and calculations are being examined.

Contextual Notes

Participants are navigating the complexities of applying Gauss's Law to a cylinder, including considerations of charge distribution and the geometry of the Gaussian surface. There are indications of confusion regarding the calculations and the assumptions made about the charge distribution.

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Homework Statement


An infinitely long cylinder of radius 4.0 cm carries a uniform volume charge density
ρ = 200 nC/m^3 What is the electric field at r = 8.0 cm


Homework Equations


I'm confused as to how to do this problem, I've tried converting from volume charge density to simply charge density λ and then solving with the equation for the E field due to an infiinite line charge, but this doesn't give me the right answer.


The Attempt at a Solution


(200 x10 ^-9)((4/3)(pi)(.04^3)) = Q

λ = Q / L so λ = Q (as we're taking L to be 1 meter in the above equation)

Efield due to infinite line charge= 2kλ/(.08)

the correct answer is supposed to be .23kN/c
 
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It looks like there is enough symmetry to use Gauss's Law.
 


SammyS said:
It looks like there is enough symmetry to use Gauss's Law.

I know but I tried finding Q as I showed above, by taking ρ = 200nC/m^3 and multiplying it by the volume (4/3 pi (.04)^3) to get Q = 5.36E-11

I then use Gauss's law: E(4pi(.08)^2) = 5.36E-11/ε0

this however gives me E = 75.306

What am I doing wrong?
 


(4/3)πR3 is the volume of a sphere of radius, R.

You should be working with a cylinder.
 


Edit: never mind I found the answer, Thanks again for the help.
 
Last edited:


A cylinder of height 1 m is OK. A radius of 4 cm will give you the charge enclosed by a cylinder of height 1 m and radius of 8 cm, which is your Gaussian surface.
 

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