Solving an equation with conditional solutions

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The discussion revolves around the mathematical function f[x_] = x^2 + c and the process of solving for x in the equation derived from its derivative, f'[f[x]] == 1. The output reveals multiple solutions for x expressed as ConditionalExpressions, indicating that the number of solutions varies based on the value of c. Specifically, for some values of c, there are three solutions, while for others, there are two or only one. The attempt to express solutions in terms of c using the Eliminate function did not yield valid results, and there is a caution regarding the verification of these solutions under the ConditionalExpression. The complexity of the relationship between the solutions and the parameter c is highlighted, emphasizing the need for careful analysis of the conditions under which these solutions exist.
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f[x_] := x^2 + c;
y = Solve[f'[f[x]] == 1, x, Reals]

output:

{{x -> ConditionalExpression[Root[-1 + 4 c #1 + 4 #1^3 &, 1],
c > -(3/4) || c < -(3/4)]}, {x ->
ConditionalExpression[Root[-1 + 4 c #1 + 4 #1^3 &, 2],
c < -(3/4)]}, {x ->
ConditionalExpression[Root[-1 + 4 c #1 + 4 #1^3 &, 3],
c < -(3/4)]}}

Then i want to put the solutions in terms of c which doesn't work with:
Eliminate[c == -x - x^2 && x == y[[1]], x]
 
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In[1]:= ToRadicals[Root[-1+4 c #1+4 #1^3&,1]]

Out[1]= ((-4*c)/(3^(1/3)*(9 + Sqrt[3]*Sqrt[27 + 64*c^3])^(1/3)) + (9 + Sqrt[3]*Sqrt[27 + 64*c^3])^(1/3)/3^(2/3))/2

but I have NOT carefully verified that this is valid under the ConditionalExpression and even if it is the solutions will still depend on the value of the unknown c.

This still leaves the situation that for some values of c there are 3 solutions, for some there are 2 and for some there are only 1.
 
Last edited:

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