Solving an Integral: ∫-sin(t)2 + cos(t)2 dt from [0;∏/4]

[aaaa202]

I don't know if this is very basic, but I'm having trouble with the integral:

∫-sin(t)2 + cos(t)2 dt from [0;∏/4]

Have tried substituting sin(t)2 = cos(t)2 - 1 but didn't really make things easier as it's the exponent that troubles me. How do you solve this integral the easiest way?

 

[Mark44]

I don't know if this is very basic, but I'm having trouble with the integral:

∫-sin(t)2 + cos(t)2 dt from [0;∏/4]

Have tried substituting sin(t)2 = cos(t)2 - 1 but didn't really make things easier as it's the exponent that troubles me. How do you solve this integral the easiest way?

cos²(t) - sin²(t) = cos(2t)

 

[Mark44]

Also, when you start a thread, don't just blow away the template parts.

 

[Ray Vickson]

I don't know if this is very basic, but I'm having trouble with the integral:

∫-sin(t)2 + cos(t)2 dt from [0;∏/4]

Have tried substituting sin(t)2 = cos(t)2 - 1 but didn't really make things easier as it's the exponent that troubles me. How do you solve this integral the easiest way?

Please try to follow standard notation; the square of a quantity x is x^2, not x2. Alternatively, you could use the "SUP" command, to get x², which was typed in as x[S U P ]2[/ S U P] but with all the spaces removed.

RGV