Solving Angular Rotation Homework: Question b, c & d

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SUMMARY

The discussion focuses on solving an Angular Rotation homework problem involving a 1kg engine rotating on a 3-meter wire. Key calculations include determining the final angular velocity (ω) after 2 minutes, the tension in the wire, the distance traveled during acceleration, and the kinetic energy upon shutdown. The final angular velocity is calculated as 0.25 rad/sec, while the kinetic energy is determined to be 21,600 J using the formula KE = 1/2(I)(angular acceleration)(T)^2. The tension in the wire and the distance traveled require further calculations based on the provided equations.

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  • Understanding of angular motion concepts, including angular velocity and acceleration.
  • Familiarity with the equations of motion for rotational dynamics.
  • Knowledge of kinetic energy calculations in rotational systems.
  • Basic proficiency in algebra and physics problem-solving techniques.
NEXT STEPS
  • Calculate the tension in the wire using centripetal force equations.
  • Determine the distance traveled by the engine during acceleration using S = rθ.
  • Explore the relationship between angular velocity and linear velocity in rotational systems.
  • Review the derivation of kinetic energy formulas for rotating bodies.
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Students studying physics, particularly those focusing on rotational dynamics, as well as educators looking for examples of angular motion problems and solutions.

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Homework Statement


A 1kg engine rotates at 1 rad/sec about a point on a 3meter wire. The engine produces an acceleration of 1 rad/sec^2 and is fird for 2 minutes.

a) What is the ω at the end of 2 minutes?
b) what's the tension in the wire at the end of 2 min.?
c) how far will the engine travel in meters while it's accelerating?
d) what's the Kinetic Energy of the engine after it shuts down?

Homework Equations


a)ω=radius/Time or ω= θ/Time
B) ?
c) S=rθ
θ= ωi(T)+1/2αT^2
d) KE=1/2(Ι)(angluar acceleration)(T)^2
Ι=1/2mr^2

The Attempt at a Solution


a) ω=radius/Time
ω=3/120= 0.25 rad/sec
b)?
c) ?
d) Ι=1/2mr^2
Ι=1/2(1)(3)^2= 3

KE=1/2(Ι)(angluar acceleration)(T)^2
KE=1/2(3)(1)(120)^2
KE=21600 J

need help with b&c and with corroborating a&d!
thanks!
 
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a) The engine is experiencing a constant angular acceleration, [tex]\alpha[/tex], while it is fired. The constant angular acceleration equations look similar to the constant linear acceleration equations:

[tex]\omega = \omega _i + \alpha t[/tex]

b) Use the final angular speed to calculate the centripetal force that the engine is experiencing, this will be the tension in the wire.

c) your equations should do the trick

d) I think the kinetic energy is given by

[tex]EK = \frac{1}{2}I \omega ^2[/tex]
 

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