Solving Block & Spool: Finishing Line & Work-Energy

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SUMMARY

The discussion focuses on the mechanics of a block and a spool being pulled across a frictionless surface by a string. Both objects have the same mass and are subjected to the same constant tension, resulting in identical accelerations. However, the spool has a greater total kinetic energy due to its rotational kinetic energy component, while both the block and spool cross the finish line simultaneously. The work done on the spool is greater because the pulling force moves a longer distance as the string unwinds.

PREREQUISITES
  • Newton's Second Law (Fnet = ma)
  • Work-Energy Theorem (W = KEf - KEi)
  • Understanding of translational and rotational kinetic energy
  • Basic principles of mechanics and forces
NEXT STEPS
  • Study the differences between translational and rotational kinetic energy
  • Learn about the implications of tension in systems with pulleys and spools
  • Explore the concept of work done by forces in mechanical systems
  • Investigate real-world applications of the Work-Energy Theorem in engineering
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Students in physics, mechanical engineers, and anyone interested in understanding the dynamics of rotational motion and work-energy principles.

Zach_Sch
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Homework Statement


A block and a spool are each pulled across a level, frictionless surface by a string.
The string wrapped around the spool will unwind as it is pulled.
Both the block and the spool have the same mass and are pulled with the same constant tension.

Which will cross the finish line (distance: d) first?
Which mass had more work done on it?
Which mass has a larger total kinetic energy and which has a larger translational kinetic energy?

Homework Equations


Newton's second law: Fnet = ma
Work-Energy Theorem: W = KEf - KEi

The Attempt at a Solution


I get that the blocks will cross the finish line at the same time, they are pulled by the same force and their masses are equal, therefor both the spool and the block have the same accelerations. (NII law)

For the work and kinetic energy questions I am a bit confused:
The equation for work is: Work = Force*Distance*cos(theta)

--- Both of the mass were pulled by the same force over the same distance so wouldn't the work done on each be identical?
But then, using the work energy theorem: Work = KEf - KEi
I get something different. The spool should have more kinetic energy at the instant it crosses the finish line due to their equivalent translational kinetic energies (velocities are also the same), but the the spool also has rotational kinetic energy, making its total kinetic energy greater than that of the block.---?
 
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Hello Zach, :welcome:
Zach_Sch said:
Both of the mass were pulled by the same force over the same distance
You sure about that ? Hint: look at this from the viewpoint of the pulling force at the other end of the string that is being pulled...
 
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BvU said:
Hello Zach, :welcome:
You sure about that ? Hint: look at this from the viewpoint of the pulling force at the other end of the string that is being pulled...

So the spool's string will unwind and the hand pulling on it will move farther than the hand pulling on the block?
Thus making the spool require more work over the distance (higher KE due to rotational + translational).
 
Zach_Sch said:
So the spool's string will unwind and the hand pulling on it will move farther than the hand pulling on the block?
Thus making the spool require more work over the distance (higher KE due to rotational + translational).
Yes.
 
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