Solving Boolean Algebra Qns: x+yz+x'y= (x+x')(x+y)+yz

[jaydunkfull]

hi all

ive got a short qns on boolean algebra. here's the qns

x+yz+x'y= (x+x')(x+y)+yz

this is just a small part of the eqn i do not understand. how does x+x'y become (x+x')(x+y)? i don't seem to be able to apply any other laws that lead to this.

thanks in advance!

 

[vela]

You can use absorption to replace x with x(x+y) and add xx' since it's equal to 0 to get

x+x'y = x(x+y) + x'x + x'y = x(x+y) + x'(x+y) = (x+x')(x+y)

Seems kind of a roundabout way to show x+x'y = x+y.