Solving Club Membership Probability Problem

  • Thread starter Thread starter chrisyuen
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary

Homework Help Overview

The problem involves calculating probabilities related to club membership demographics, specifically focusing on smokers and non-smokers among male and female members. The questions ask for the probability of selecting a male member and the probability of a female member being a non-smoker.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of probability formulas and tree diagrams to analyze the problem. There are attempts to clarify the relationships between different probabilities, particularly regarding conditional probabilities.

Discussion Status

Some participants have provided guidance on the correct application of probability formulas and have pointed out potential errors in the original poster's reasoning. Multiple interpretations of the problem are being explored, and there is an ongoing examination of the tree diagram's accuracy.

Contextual Notes

Participants are working with specific probabilities given in the problem statement, and there is a focus on ensuring that the relationships between these probabilities are correctly understood. The discussion reflects a learning process with no definitive conclusions reached yet.

chrisyuen
Messages
55
Reaction score
0

Homework Statement



In a certain club, one-fifth of its members are smokers. One-sixth of its male members are smokers. Among the non-smoking members, one-eighth are female. A member is randomly chosen.

(a) What is the probability that this member is male;
(b) If this member is female, what is the probability that she is a non-smoking member.

(Answers:
(a) 21/25
(b) 5/8)

Homework Equations



Probability Formulae

The Attempt at a Solution



One of my friends told me the followings in order to get the final answer correct.

However, I don't know how can he get them.

(a)
(1 - 1/5) * (1 - 1/8) / (1 - 1/6)
= 7/10 / (5/6)
= 21/25
(b)
(1 - 1/5) * 1/8 / (1 - 21/25)
= 1/10 / (4/25)
= 1/10 * 25/4
= 5/8

I tried to write a tree diagram as follows:

S = 1/5
NS = 4/5

S.M = 1/6
S.F = 5/6

NS.M = 7/8
NS.F = 1/8

S: Smoker; NS: Non-Smoker; M: Male; F: Female

Did my tree diagram correct?

My attempt on part (a):
P(M)
= P(M|S)P(S) + P(M|NS)P(NS)
= 1/6 * 1/5 + 7/8 * 4/5
= 11/15

My attempt on part (b):
P(NS|F)
= P(NS and F) / (P(F|S)P(S) + P(F|NS)P(NS))
= 4/5 * 1/8 / (1/5 * 5/6 + 4/5 * 1/8)
= 3/8

But my answers are not correct.

Can anyone tell me how to solve this question?

Thank you very much!
 
Physics news on Phys.org
P(S|M) is not the same as P(M|S) this was your error on both the parts. Do you know the formula to obtain P(M|S) from P(S|M)?
 
Focus said:
P(S|M) is not the same as P(M|S) this was your error on both the parts. Do you know the formula to obtain P(M|S) from P(S|M)?

P(S|M)
= P(S and M) / P(M)
= P(M|S)P(S) / P(M)?

Did my tree diagram correct?

Thank you very much!
 
chrisyuen said:
P(S|M)
= P(S and M) / P(M)
= P(M|S)P(S) / P(M)?

Did my tree diagram correct?

Thank you very much!

I don't know about tree diagrams but one of them looks false. Try to just write it out as P(A|B). "One-sixth of its male members are smokers", what are you given?

As an example, 2/5 of the women population read Heat magazine, so P(reading heat| it's a woman)=2/5. The information given to you is that it is a woman, restated it says given that the person is a woman, the probability of the person reading Heat is 2/5.

Your formula is correct (Bayesian formula). Try to rethink about what the question says. I hope that example helps. If not let me know.
 
P(NS|M)
= P(M|NS) P(NS) / P(M)

P(M)
= P(M|NS) P(NS) / P(NS|M)
= P(M|NS) P(NS) / (1 - P(S|M))
= 7/8 x 4/5 / (1 - 1/6)
= 21/25

P(NS|F)
= P(F|NS) P(NS) / P(F)
= P(F|NS) P(NS) / (1 - P(M))
= 1/8 x 4/5 / (1 - 21/25)
= 5/8

Am I right?
 
chrisyuen said:
P(NS|M)
= P(M|NS) P(NS) / P(M)

P(M)
= P(M|NS) P(NS) / P(NS|M)
= P(M|NS) P(NS) / (1 - P(S|M))
= 7/8 x 4/5 / (1 - 1/6)
= 21/25

P(NS|F)
= P(F|NS) P(NS) / P(F)
= P(F|NS) P(NS) / (1 - P(M))
= 1/8 x 4/5 / (1 - 21/25)
= 5/8

Am I right?

Yep looks fine to me :approve:
 
Focus said:
Yep looks fine to me :approve:

Thanks for your helps!
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
1
Views
1K
Replies
2
Views
1K
Replies
15
Views
4K
Replies
6
Views
3K
Replies
31
Views
7K
Replies
2
Views
2K
Replies
3
Views
1K