Solving Complex Equations with x, y, z

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Discussion Overview

The discussion revolves around solving the equation x = ay - (a^2)z for the variable a, with participants exploring methods for finding a solution given that x, y, and z are complex formulas. The scope includes mathematical reasoning and problem-solving techniques.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant initially seeks to solve for a but expresses concern that the quadratic method may not be applicable due to the complexity of x, y, and z.
  • Another participant asserts that the quadratic formula will always work, although the resulting solution may be complex if x, y, and z are complex.
  • A later reply provides the quadratic formula for solving the equation, indicating the form of the solution.
  • One participant expresses a desire for a solution using the quadratic method and notes the distinct nature of the variables involved.
  • Another participant recalls the name associated with the quadratic formula but cannot remember it, indicating a lapse in their mathematical practice.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the applicability of the quadratic formula given the complexity of the variables. Some express doubt about its utility, while others maintain that it is a valid approach.

Contextual Notes

There are unresolved assumptions regarding the nature of the complex formulas for x, y, and z, which may affect the applicability of the quadratic method. The discussion does not clarify the specific complexities involved.

dE_logics
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I got this equation -

x = ay - (a^2)z

Solve for a...and apart from the factorization method, is there any other way?...cause the constants x, y, z are very complex formulas.
 
Last edited:
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Are you trying to solve for a or x (the thread title says a, your post says x). If you're solving for x, you just did it... if you're solving for a, just use the quadratic formula. Maybe I'm missing something
 
Extremely sorry about that...gotta solve for a

Actually x, y, z are very complex (as said) so the quadratic method...I think will not work.
 
The quadratic formula will always "work". It will just be a very complex solution if x, y, and z are. But no other method is certain to work- and if it did would have to give the same, complex, solution.
 
humm...ok then, can anyone pls solve it in the quadratic way?...cause we have completely distinct variables...x, y and z.

Then I'll replace the values after the solution.
 
You have za2 - you + x = 0. So the quadratic formula is:

[tex]a = \frac{y +/- \sqrt{y^2-4xz}}{2z}[/tex]
 
Oh yes...I remember...the name of the formula I forgot though...it was someone's name right?...starting with s.


Anyway...thanks man!


Not done maths for a long time.
 

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