Solving Conduction Heat Wave in Metal Bar

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Homework Help Overview

The discussion revolves around a problem involving the conduction heat wave in a metal bar, described by a sinusoidal temperature equation. The original poster seeks to understand how to extract the amplitude and wavelength from the given equation, which involves temperature variations over time and space.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the meaning of amplitude and how it relates to the wave equation provided. There are questions about substituting values for position and time to find temperature, as well as clarifications on the interpretation of the equation.

Discussion Status

Some participants have offered guidance on identifying the amplitude from the wave equation, while others are exploring the implications of the temperature equation. There is an ongoing inquiry into the correct substitution of values for specific conditions, with some participants questioning the accuracy of the results obtained.

Contextual Notes

Participants note the importance of unit conversion, specifically converting millimeters to meters, as a potential source of error in calculations. There is also a mention of the need for clarity on how to interpret the sinusoidal temperature equation in the context of the problem.

roam
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Homework Statement



A conduction heat wave is caused to pass through a metal bar of average temperature Tmean = 35.0 °C, altering its temperature sinusoidally with an amplitude of Ti = 2.0 °C. The equation which gives the temperature, T(x,t), of the metal bar at any place x (in meters) inside it at any time t (in seconds) is:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co ]

where Co = 1.0π.

(a) What is the amplitude of the wave? (b) What is the wavelength of the wave?


Homework Equations



  • Speed of sound wave (where B is the bulk modulus and mu p is the pressure): v=\sqrt{\frac{B}{\rho}}
  • Power of sinusoidal wave: P=\frac{1}{2} \mu \omega^2 A^2 v
  • For sound traveling through air:v=(331)\sqrt{1+\frac{T_C}{273}}

  • Wave function for a sinusoidal wave: y=A sin(kx-\omega t)

The Attempt at a Solution



I don't understand how to apprach this problem. For example for part (a), what formula can I use? Also how do I find the temprature using the given equation:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co ]

what values do I need to substitute for "x" and "t"?
 
Last edited:
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roam said:
Also how do I find the temprature using the given equation:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co ]
Where does it ask you to find the temperature? :confused:
roam said:
what values do I need to substitute for "x" and "t"?
The temperature is different at different positions and different times. To find the temperature at a specific point in space and at a specific time, you would substitute in the position coordinate (x) of that point in space, and the time coordinate t.

Part (a) asks you for the amplitude of the wave. Do you know what amplitude means? Do you know how to find it from a wave equation? For instance, the equation
y=A \sin(kx - \omega t)
represents a wave. What would be the amplitude of that wave?
 
diazona said:
Part (a) asks you for the amplitude of the wave. Do you know what amplitude means? Do you know how to find it from a wave equation? For instance, the equation
y=A \sin(kx - \omega t)
represents a wave. What would be the amplitude of that wave?

"A" represents the amplitude. But how should I find the amplitude in this particular problem? The equation given only describes the temprature not the wave.
 
Well, you know that
y(x,t)=A \sin(kx - \omega t)
represents a wave, right? Do you also accept that
y(x,t) = y_\text{mean} + A \sin(kx - \omega t + \phi)
represents a wave? (How would you find its amplitude?)

If so, what's the problem? The equation
T(x,t) = T_\text{mean} + T_i \sin[2\pi(0.027t - 3.0x) + C_0]
is exactly the same thing, just with different letters.
 
Thanks, I get it now. :smile:

Here's my last question: they further ask "What is the value of T(x,t) when t = 170.0 s, and x = 210.0 mm?"

I simply substituted the given values of "t" and "x" (along with other previously given values) into the equation:

T(x,t) = Tmean + Ti sin[ 2π(0.027t – 3.0x) + Co]

But the value I got was not the correct answer. Why is that? :confused:
 
did u convert into metres?
 
Killeregg said:
did u convert into metres?

40 mm = 0.04 m

37 sin(2 \pi (0.027(130)-3(0.04)+)\pi) = -23.5

But the correct answer must be 33.7! Why??
 

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