Solving Curve Function: Intercepts, Parabola Help

  • Context: High School 
  • Thread starter Thread starter cgaday
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    Curve Function
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Discussion Overview

The discussion revolves around finding the equation of a parabolic curve given specific intercepts and understanding the implications of integration for area calculations under the curve. Participants explore the relationship between the curve's intercepts, its equation, and the area under the curve, with a focus on both positive and negative areas as they relate to the x-axis.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant states the y-intercept is 1 and the x-intercepts are 4 and -4, leading to the conclusion that the function is a parabola.
  • Another participant suggests the equation can be expressed as y = a(x-4)(x+4) and questions the value of a that would satisfy the y-intercept condition.
  • There is a discussion about the integration of the quadratic function and why the area calculated can be negative, with some participants suggesting that the area under the x-axis contributes negatively to the total area.
  • Participants explore the implications of changing the y-intercept to a negative value and whether that would result in a negative area, with some asserting that a negative area indicates an error in setting up the integral.
  • One participant expresses confusion over integrating a function with a negative y-intercept and receives clarification on how to correctly set up the integral to avoid negative area results.
  • Another participant presents a new quadratic function with different intercepts and a y-intercept, questioning the negative area obtained from their integration and seeking clarification on the setup of the integral.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct setup for integration and the interpretation of negative areas. There are competing views on how to handle the integration of functions that cross the x-axis and how to derive the correct equation from given intercepts.

Contextual Notes

Some participants mention specific limits of integration and the need to consider the behavior of the curve relative to the x-axis, highlighting that the area calculation depends on the correct interpretation of the function's position relative to the axis.

Who May Find This Useful

This discussion may be useful for students or individuals studying quadratic functions, integration techniques, and the geometric interpretation of areas under curves in mathematics.

  • #31
Mostly, I left things as fractions, writing 4.5 as 9/2, for example, so 4.5^2 = 81/4. Also, 1/4 inch = 1/48 ft.
 

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