Solving Differential Equations to Finding Solutions

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Homework Help Overview

The discussion revolves around solving a differential equation of the form \(\dot{x} = Hx_0 \left( \sqrt{B} \frac{x_0}{x} + \sqrt{1-A-B} \right)\), with participants exploring various methods and interpretations related to the equation's components.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the potential use of the integrating factor method and question the nature of the constants A, B, H, and \(x_0\). There is an attempt to simplify the equation by introducing new variables U and V, leading to a reformulation of the problem.

Discussion Status

The discussion is ongoing, with some participants providing guidance on variable substitution and integration techniques. However, there remains uncertainty regarding the constants and the complexity of solving for \(x\) after integration.

Contextual Notes

Participants express a need for clarification on whether A, B, H, and \(x_0\) are constants, which affects the approach to the problem. There is also mention of the difficulty in solving for \(x\) after integration.

Logarythmic
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Can anyone help me solve

[tex]\dot{x} = Hx_0 \left( \sqrt{B} \frac{x_0}{x} + \sqrt{1-A-B} \right)[/tex]
 
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Logarythmic said:
Can anyone help me solve

[tex]\dot{x} = Hx_0 \left( \sqrt{B} \frac{x_0}{x} + \sqrt{1-A-B} \right)[/tex]

what is what? in any case, try integrating factor method
 
It's equivalent to solving

[tex]y \frac{dy}{dx} + ay + b = 0[/tex]
 
We need more information. Are you saying that A, B, H, and x0 are constants? Is so, simplify by letting
[tex]U= \frac{H\sqrt{B}x_0^2}{x}[/tex]
and
[tex]V= Hx_0\sqrt{1- A- B}[/itex]<br /> <br /> So your equation becomes <br /> [tex]\frac{dx}{dt}= \frac{U}{x}+ V= \frac{U+ Vx}{x}[/tex]<br /> [tex]\frac{xdx}{U+ Vx}= dt[/itex]<br /> <br /> That's easy to integrate.[/tex][/tex]
 
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Then I get

[tex]t= \frac{x}{V} -\frac{U}{V^2}ln(Vx+U)[/tex]

and trying to solve this for x is rather difficult?
 

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