MHB Solving $\displaystyle \int \frac{\ln\left(x^2+2\right)}{(x+2)^2}dx$ by Parts

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The discussion focuses on solving the integral $\int \frac{\ln(x^2+2)}{(x+2)^2}dx$ using integration by parts, leading to the expression $-\ln(x^2+2)\cdot \frac{1}{(x+2)} + 2\int \frac{x}{(x^2+2)(x+2)}dx$. There is a debate about the use of partial fraction decomposition as a method for solving the remaining integral, with some participants advocating for it as the best approach. Others emphasize the importance of exploring alternative methods to foster creativity in problem-solving. Overall, the conversation highlights the balance between standard techniques and the encouragement of innovative solutions in mathematics.
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$\displaystyle \int \frac{\ln\left(x^2+2\right)}{(x+2)^2}dx$

$\bf{My\; Try::}$ Given $\displaystyle \int \ln \left(x^2+2\right)\cdot \frac{1}{(x+2)^2}dx$

Using Integration by parts, we get

$\displaystyle = -\ln\left(x^2+2\right)\cdot \frac{1}{(x+2)} + 2\int \frac{x}{\left(x^2+2\right)\cdot (x+2)}dx$

Is there is any other method by which we can solve the Integral

$\displaystyle \int \frac{x}{\left(x^2+2\right)\cdot (x+2)}dx$ other then partial fraction.

Help me

Thanks
 
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Why the aversion to partial fraction decomposition? I think it is the best course of action for continuing. :D
 
I agree with Mark, the best strategy would be partial fractions.

Try $\displaystyle \begin{align*} \frac{A\,x + B}{x^2 + 2} + \frac{C}{x + 2} \equiv \frac{x}{ \left( x^2 + 2 \right) \left( x + 2 \right) } \end{align*}$ for your partial fraction decomposition.
 
Thanks Markfl and prove it.
 
While partial fractions is fine/the standard way, asking for an alternative way is something I feel should always be encouraged (and never discouraged) in mathematics. Looking for alternative ways to do problems builds one's creativity far better than sticking to the usual methods.
 

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