Solving Euler's Formula: 2^(1-i) Explained

Join the discussion

Registration is free. Ask a follow-up in this thread, or start your own.

1 reply · 2K views

btbam91

Hey guys, I'm having trouble on understanding how:

2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!

Discussion

Physics news on Phys.org

logarithmic

btbam91 said:

Hey guys, I'm having trouble on understanding how:

2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!

2^(1-i) = exp(ln[2^(1-i)]), go from there.