Solving First-Order Kinetics for [B] After 7.00 Minutes

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SUMMARY

The discussion focuses on solving first-order kinetics for the reaction A → B, with a rate constant k of 0.30 / min and an initial concentration of [A] at 0.54 M. After 7.00 minutes, the remaining concentration of [A] is calculated to be 0.066 M using the formula Ln[A]/[Ao] = -kt. However, the correct interpretation reveals that the amount of product [B] formed is 0.47 M, as the difference between the initial concentration of [A] and the remaining concentration must be accounted for.

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geffman1
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We examine the reaction A B which displays first-order kinetics. We know that k = 0.30 / min.
If we begin with [A] = 0.54 M what will be after exactly 7.00 minutes?


hey i used the formula In[A]/[Ao]=-kt then rearranged to In[A]=-kt+[InAo]
when i sub it in i get In[A]=-0.3x7+In[0.54] and i get the answer 0.066 however the answer is 0.47M. i tired converting to second and still didnt work. any help would be good. thanks
 
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There's nothing wrong with your math.* The amount of [A] left is 0.066. The question is not asking you for the amount of [A] left. It is asking you for the amount of produced.

*Well, other than the fact that it is supposed to be Ln, not In. Natural Logarithm.
 
ta, how do i work out how much is produced?
 
dw, I am stupit. thanks mate
 
A is being converted to B in this chemical reaction, right? If 0.066 is left, what happened to the rest of it? It became B.
 

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