Solving Fluid Mechanics Question: Forces on Plane Areas

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SUMMARY

The discussion focuses on calculating forces on plane areas submerged in fluid, specifically when water acts below a gate. The key concepts include hydrostatic pressure, which varies linearly with depth, and the balance of moments around the hinge of the gate. The pressure at the top is expressed as mgH, while at the bottom it is mg(H+4). The local force is determined by the pressure function p(x sinθ), where θ is the angle of the gate, and the moment is calculated as x*f(x).

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philharg
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Ok I have a question that I am stuck on which is about forces on plane areas. I can do the questions ok where the water acts aboce the gate but in this case the water acts below it if you get what i mean. Can someone please give an explanation of the approach to this question and how you do it, I would be very grateful. Picture is below:

http://img503.imageshack.us/img503/2701/dscf0244yo0.jpg
 
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The gate has a distributed force, which is a function of distance (height) from the pivot (hinge). The local force is due to the hydrostatic pressure of the fluid, which is a function (mgh) of the height (depth) of water above that point. At the top of the gate, the pressure is mgH, and at the bottom the water pressure is mg(H+4), and it varies linearly in between.

The problem requires a balance of moments. The pressure varies along the face of the plate normal to the surface and parallel to force P.

The moment of P must equal the moment of the force generated by the water pressure on the area of the gate.

Let x be the distance from the hinge, and the pressure varies as p(x sin\theta), where \theta the angle between the plane of the gate and the horizontal. The force is p*A and assuming unit width, an increment of area is given by 1*dx, so the local force at x is f(x) = p(x)dx, the moment of the force if x*f(x).
 

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