Solving for Acceleration using V^2=V0^2+2a(x-x0)

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To find the acceleration of a hockey puck with an initial velocity of 49 m/s and a final velocity of 35 m/s over a distance of 25 m, the equation V^2 = V0^2 + 2a(x - x0) can be used. The correct approach involves identifying V as the final velocity and V0 as the initial velocity, with (x - x0) representing the distance traveled. One user initially misapplied the equation, resulting in an incorrect negative acceleration value. Properly rearranging the equation allows for solving the acceleration accurately. Understanding the correct variables is crucial for applying the formula effectively.
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1. A hockey puck has an initial velocity of 49 m/s and a final velocity of 35 m/s. If it travels 25 m during this time, what is the acceleration?


2. V^2=V0^2+2a(x-x0)



3. I can't even begin the above equation because I don't know what my velocity is. I tried putting my final velocity in the above equation as V^2 and got -.28 m/s^2. It was wrong. I am assuming that is not how the equation is supposed to be used. Please help!
 
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welcome to pf!

hi tball665! welcome to pf! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)

V is the final velocity, and Vo is the initial velocity :wink:
 


since (X-X0) is 25-0

you can move variables around and solve for a
 

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