Solving for Angular Frequency of 2 Masses on a Spring

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SUMMARY

The angular frequency of a system consisting of two identical masses, each of mass m, attached to a spring with spring constant k on a frictionless surface is determined by the formula ω=√(k/2m). The total mass of the system is 2m, leading to the conclusion that the angular frequency is inversely proportional to the square root of the total mass. This indicates that the system oscillates slower than if only one mass were present, confirming that the initial assumption of a faster oscillation was incorrect.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with the concept of angular frequency
  • Knowledge of spring constants and Hooke's law
  • Basic principles of oscillatory motion
NEXT STEPS
  • Study the derivation of angular frequency in harmonic oscillators
  • Explore the effects of varying mass on oscillation frequency
  • Learn about coupled oscillations and their applications
  • Investigate the role of damping in oscillatory systems
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking for clear examples of angular frequency calculations in spring-mass systems.

usamo42j
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Homework Statement


Two identical objects of mass m are placed at either end of a spring of spring constant k and the whole system is placed on a horizontal frictionless surface. At what angular frequency ω does the system oscillate?


Homework Equations


ω=√(k/m)


The Attempt at a Solution



Total mass is 2m, so ω=√(k/2m)

Apparently that's not right, though my answer does not really seem reasonable, as it should be oscillating faster than with one mass...?
 
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Hi usamo,

Write out Newton's second law for both bodies.

ehild
 

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