A box, mass 100kg, must be pushed onto a table using an inclined plane 1.5 m high. The plane is 4 m long. If the pleane offers a frictional force equivalent to 10% the weight of the box, what force must be applied to move the box? What I tried: sin^-1(4/1.5) = 22.6 100 * 9.8 = 980 N (fgrav) 980cos22.6=904.77N (Fperpendicular) Ffrict=10%980=98N That's where I get stuck. I'm not sure if I'm even doing it right (However, I know the angle is). Please help. My exam is tomorrow.