Solving for Car Mass with Gauge Pressure and Surface Area | Physics Problems

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The discussion focuses on solving physics problems related to fluid mechanics, specifically calculating mass using gauge pressure and surface area. The gauge pressure in car tires is given as 240 kPa, with each tire's footprint area of 220 cm², leading to the conclusion that the estimated mass of the car is approximately 2.2 x 10^3 kg. Another problem involves calculating the cargo capacity of a helium balloon, where the buoyant force must exceed the combined weight of the balloon structure, helium, and cargo, resulting in a maximum cargo mass of about 920 kg. The third problem addresses determining the density of a metal sample based on its mass in air and apparent mass in water, ultimately identifying it as iron or steel. The discussion emphasizes the importance of unit conversions and applying buoyant force equations for accurate calculations.
  • #31
jrd007 said:
Isn't bouyancy force = pVg? - I know neither p(denisty) or volume or the Fb so how can I solve for it?
The fluid is water, so you should know the density. Also: true weight - buoyant force = apparent weight.
 
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  • #32
denisty of water is 1000 kg/m^3

So since mass is 63.5 I just divide that by the volume and tha give me density?
 
  • #33
Yes. Once you figure out the volume you can get the density by \rho = m/V. (Be careful with units.)
 
  • #34
yes but is it not jus 63.5/1000 ? I thought that was why I was trying to find the volume of water?
 
  • #35
1000 kg/m^3 is the density of water, not the volume of water displaced. (You'll need the density and the buoyant force to solve for the volume.)
 
  • #36
Actually you you can just minus the two to get the water displaces and change it into kg = .0081

63.5/.0081 = 7839! :)
 

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