Solving for Common Root in $(1)$ and $(2)$

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SUMMARY

The discussion focuses on finding the common root of two quadratic equations: $(a-1)x^2-(a^2+2)x+(a^2+2a)=0$ and $(b-1)x^2-(b^2+2)x+(b^2+2b)=0$. It establishes that for these equations to share a root, specific conditions on the parameters $a$ and $b$ must be met, particularly that $a$ and $b$ are natural numbers greater than 1 and not equal to each other. The final goal is to compute the expression $\dfrac{a^a+b^b}{a^{-b}+b^{-a}}$ based on these parameters.

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Albert1
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$(a-1)x^2-(a^2+2)x+(a^2+2a)=0----(1)\\
(b-1)x^2-(b^2+2)x+(b^2+2b)=0----(2)
$
if $(1)$ and $(2)$ have one root in common ,
(here $a,b\in N$ ,$a\neq b,\,\, and \,\, a>1,b>1$)
find value of :
$\dfrac{a^a+b^b}{a^{-b}+b^{-a}}$
 
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Albert said:
$(a-1)x^2-(a^2+2)x+(a^2+2a)=0----(1)\\
(b-1)x^2-(b^2+2)x+(b^2+2b)=0----(2)
$
if $(1)$ and $(2)$ have one root in common ,
(here $a,b\in N$ ,$a\neq b,\,\, and \,\, a>1,b>1$)
find value of :
$\dfrac{a^a+b^b}{a^{-b}+b^{-a}}$
hint
(1) and (2) can be factorized
 

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