Solving for Distance of Crate on Level Floor with Given Force & Time

[klr872]

A 29.8kg crate is at rest on a level floor, and the coefficient of kinetic friction is 0.338. The acceleration of gravity is 9.8 m/s. if the crate is pushed horizontally with a force of 188.535 N, how far does it move in 5.88 seconds?

i really need help with this...thanks!

 

[pixel01]

So use Newton2 law's formulae: F=ma; s=(at^2)/2

 

[klr872]

so i did 188.535= (29.8) (A)
A= 6.33

D=(6.33)(5.88)^2 /2
=109.43

but that's not the right answer i don't know what I am doing wrong

 

[rock.freak667]

The weight of the box is 29.8*9.81= (*)N
therefore the normal reaction,R= (*) N

the frictional force=uR where u=coefficient of friction.

find the resultant force and then equate that to ma