Solving for Distance of Crate on Level Floor with Given Force & Time

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Homework Help Overview

The discussion revolves around calculating the distance a crate moves on a level floor when subjected to a horizontal force, considering the effects of friction. The problem involves concepts from dynamics and kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore Newton's second law and kinematic equations to relate force, mass, and acceleration. There are attempts to calculate acceleration and distance, but some participants express uncertainty about their calculations and results.

Discussion Status

Some participants have provided initial calculations and approaches, while others are questioning the correctness of these calculations. There is an ongoing exploration of the forces acting on the crate, including friction, but no consensus has been reached on the correct method or answer.

Contextual Notes

Participants are working with given values such as mass, force, and time, but there are indications of missing details regarding the normal force and frictional force calculations, which are critical for resolving the problem accurately.

klr872
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A 29.8kg crate is at rest on a level floor, and the coefficient of kinetic friction is 0.338. The acceleration of gravity is 9.8 m/s. if the crate is pushed horizontally with a force of 188.535 N, how far does it move in 5.88 seconds?

i really need help with this...thanks!
 
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So use Newton2 law's formulae: F=ma; s=(at^2)/2
 
so i did 188.535= (29.8) (A)
A= 6.33

D=(6.33)(5.88)^2 /2
=109.43

but that's not the right answer i don't know what I am doing wrong
 
The weight of the box is 29.8*9.81= (*)N
therefore the normal reaction,R= (*) N

the frictional force=uR where u=coefficient of friction.

find the resultant force and then equate that to ma
 

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