Solve for g in terms of d, t, and theta on an inclined plane.
Fnet=ma and d=Vit + .5a*t^2
The Attempt at a Solution
Solving for a on an inclined plane I get g*sin theta.
Using the equation for constant acceleration d=Vit + .5a*t^2 I solve for g.
Vi is 0 on an initial plane so I have d=.5(g*sin theta)t^2
Is this correct?