The discussion focuses on deriving the gravitational acceleration (g) in terms of distance (d), time (t), and the angle of inclination (theta) on an inclined plane. The solution utilizes the equations of motion, specifically Fnet=ma and d=Vit + 0.5a*t^2. The correct formula derived is g=2d/(sin theta*t^2), confirming that the initial velocity (Vi) is zero on the inclined plane.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators seeking clear examples of gravitational calculations in motion.
mysticbms said:Homework Statement
Solve for g in terms of d, t, and theta on an inclined plane.
Homework Equations
Fnet=ma and d=Vit + .5a*t^2
The Attempt at a Solution
Solving for a on an inclined plane I get g*sin theta.
Using the equation for constant acceleration d=Vit + .5a*t^2 I solve for g.
Vi is 0 on an initial plane so I have d=.5(g*sin theta)t^2
g=2d/(sin theta*t^2)
Is this correct?