Solving for Horizontal Distance and Angle of Release in Dive Bomber Problem

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Homework Help Overview

The problem involves a bomber flying horizontally at a specific altitude and speed, with questions regarding the horizontal distance a bomb will travel before impact and the angle at which a bombsight should be set for accurate targeting. The subject area includes kinematics and projectile motion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the horizontal distance based on time of fall and speed, while expressing confusion about the angle of release for the bombsight. Other participants question the effective angle of the bomb's trajectory and seek clarification on the relationship between the horizontal distance, altitude, and the angle.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the angle question and seeking clarification on the problem setup. Some guidance has been offered regarding the relationship between the horizontal distance and the angle, but no consensus has been reached.

Contextual Notes

There is uncertainty regarding whether a diagram is necessary for understanding the problem, and participants are considering the implications of the angle in relation to the vertical and horizontal planes.

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A bomber is flying horizontally over level terrain, with a speed of 265 m/s relative to the ground, at an altitude of 3200 m. Neglect the effects of air resistance.

(a) How far will a bomb travel horizontally between its release from the plane and its impact on the ground?


(b) At what angle from the vertical (less than 90°) should the telescopic bombsight be set so that the bomb will hit the target seen in the sight at the time of release?

Hey,

So this problem has been giving me a little trouble.

I believe I have solved for part A correctly:
vy^2 = -2g(change in y)
vy^2 = -2(-9.8)(3200)
vy = 250.4396

vy = -gt
250.4396 = 9.8t
t = 25.5551

horizontal distance = 25.5551 x 265 = 6772.10 m

I am really having trouble understanding what part B is asking for. If someone could put me in the right direction, I would really appreciate it.

Thanks
 
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What is the effective angle that the bomb falls at?
 
Ok so this may seem like a stupid question, but what exactly does that mean? I cannot think of a formula to relate to this...i am guessing i want to set up something up that will allow me to determine the angle at which the bomb is dropped that allows it to have enough time to hit the target accurately. Basically, I need to determine the at what angle the bomb will hit its target given a time

So in this case, It takes the bomb 25.56 seconds to fall and it covers a horizontal distance of 6772.10 meters and hits the ground. I cannot figure out how to determine whether or not the bomb will have accurately hit the target...if someone could give me a little nudge in the right direction that would be great
 
Does the question involve a picture? I just want to know if you are looking for the angle between the line of sight and the vertical or between the line of sight and the horizonatal...I would assume it is the former (vertical).
 
Edit: I should have read the OP more carefully. Sorry:rolleyes: Have you by any chance drawn a picture of this?
Hint:
Photo23.jpg
Do you know of a relationship between the horizontal distance X, the altitude Y and the angle phi? What do you know about the right triangle that the projectile's effective line (the red one:) cuts out?
 
Last edited:

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