Solving for Index of Refraction: 110 Degrees Angle

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The discussion revolves around calculating the index of refraction of varnish based on the angle of reflection and incidence. The problem states that the angle between the incident and reflected rays is 110 degrees, leading to confusion about how to apply the correct formulas. Participants clarify that the angle of incidence equals the angle of reflection, and the polarizing angle must be determined from the given information. The correct approach involves using the relationship between the angles and applying Brewster's angle formula. A diagram is recommended to visualize the angles and solve for the index of refraction accurately.
matt72lsu
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Homework Statement


While studying physics at the library late one night, you notice the image of the desk lamp reflected from the varnished tabletop. When you turn your Polaroid sunglasses sideways, the reflected image disappears.

If this occurs when the angle between the incident and reflected rays is 110 degrees, what is the index of refraction of the varnish?


Homework Equations



tan theta = n2/n1

The Attempt at a Solution


I used n2 = air (1) and solved for n1 but was incorrect. Where am I going wrong?
 
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Well because it is reflected, it sounds like you have a case of total internal reflection. You'll need to use sinC = 1/n.
 
matt72lsu said:

Homework Statement


While studying physics at the library late one night, you notice the image of the desk lamp reflected from the varnished tabletop. When you turn your Polaroid sunglasses sideways, the reflected image disappears.

If this occurs when the angle between the incident and reflected rays is 110 degrees, what is the index of refraction of the varnish?


Homework Equations



tan theta = n2/n1

The Attempt at a Solution


I used n2 = air (1) and solved for n1 but was incorrect. Where am I going wrong?

Ah so close. You are correct in using the Brewster's angle formula. However notice the trick in the problem. They tell you the angle between the rays NOT the angle the rays make with normal.
 
so would i do 180-110 or something like that? the angle thing is messing me up
 
matt72lsu said:
so would i do 180-110 or something like that? the angle thing is messing me up
No.
During reflection angle of incidence is equal to angle of reflection. In the problem, the sum of the angle of incidence and angle of reflection is given. from that find the angle of incidence which is the polarizing angle.
 
Yes what rl.bhat said is correct. If you are still having trouble thinking about it, try drawing a diagram and setting the reflected and incident angles to the normal equal. Also set the angle between the two rays equal to 110.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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