Solving for Index of Refraction: 110 Degrees Angle

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SUMMARY

The discussion centers on calculating the index of refraction of varnish when the angle between incident and reflected rays is 110 degrees. Participants clarify that the angle provided is the sum of the angle of incidence and angle of reflection, which must be divided to find the polarizing angle. The correct approach involves using the Brewster's angle formula and recognizing that the angle of incidence equals the angle of reflection. The final calculation requires applying the formula sinC = 1/n to determine the index of refraction accurately.

PREREQUISITES
  • Understanding of Snell's Law and total internal reflection
  • Familiarity with Brewster's angle and its application
  • Basic trigonometry, specifically tangent and sine functions
  • Knowledge of light behavior at interfaces between different media
NEXT STEPS
  • Study the derivation and application of Brewster's angle in optics
  • Learn about Snell's Law and its implications in various media
  • Explore the concept of total internal reflection and its conditions
  • Practice problems involving the calculation of indices of refraction for different materials
USEFUL FOR

Physics students, educators, and anyone interested in optics and the behavior of light at material interfaces will benefit from this discussion.

matt72lsu
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Homework Statement


While studying physics at the library late one night, you notice the image of the desk lamp reflected from the varnished tabletop. When you turn your Polaroid sunglasses sideways, the reflected image disappears.

If this occurs when the angle between the incident and reflected rays is 110 degrees, what is the index of refraction of the varnish?


Homework Equations



tan theta = n2/n1

The Attempt at a Solution


I used n2 = air (1) and solved for n1 but was incorrect. Where am I going wrong?
 
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Well because it is reflected, it sounds like you have a case of total internal reflection. You'll need to use sinC = 1/n.
 
matt72lsu said:

Homework Statement


While studying physics at the library late one night, you notice the image of the desk lamp reflected from the varnished tabletop. When you turn your Polaroid sunglasses sideways, the reflected image disappears.

If this occurs when the angle between the incident and reflected rays is 110 degrees, what is the index of refraction of the varnish?


Homework Equations



tan theta = n2/n1

The Attempt at a Solution


I used n2 = air (1) and solved for n1 but was incorrect. Where am I going wrong?

Ah so close. You are correct in using the Brewster's angle formula. However notice the trick in the problem. They tell you the angle between the rays NOT the angle the rays make with normal.
 
so would i do 180-110 or something like that? the angle thing is messing me up
 
matt72lsu said:
so would i do 180-110 or something like that? the angle thing is messing me up
No.
During reflection angle of incidence is equal to angle of reflection. In the problem, the sum of the angle of incidence and angle of reflection is given. from that find the angle of incidence which is the polarizing angle.
 
Yes what rl.bhat said is correct. If you are still having trouble thinking about it, try drawing a diagram and setting the reflected and incident angles to the normal equal. Also set the angle between the two rays equal to 110.
 

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