The discussion focuses on solving the equation (|k1|)(|k2|)=1, concluding that k1 and k2 must equal +/- 1. The participants clarify that to demonstrate this, one must analyze four specific cases: k1 = 1, k2 = 1; k1 = -1, k2 = 1; k1 = 1, k2 = -1; and k1 = -1, k2 = -1. It is established that k1 and k2 are integers for the equality to hold true, as the statement does not apply to non-integer values.
PREREQUISITESMathematics students, educators, and anyone interested in understanding integer equations and case analysis methodologies.
You don't need to do that. You have to consider four cases: k1 = 1, k2 = 1; k1 = -1, k2 = 1; etc. For each case, you have to show that the equality holds.fk378 said:I don't know how to show that abs value of k1=abs value k2=1.