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Classify the origin of the system and draw the phase portrait

  1. Nov 8, 2011 #1
    1. The problem statement, all variables and given/known data

    Draw the phase portrait and classify the origin of the system:

    xdot = [1 2; 2 1]x

    2. Relevant equations

    characteristic equation:

    det(A-lambda*I) = 0

    3. The attempt at a solution

    First find the eigenvalues and eigenvectors:

    det(A-lambda*I) = (lambda+1)(lambda-3) = 0


    we can see that the eigenvalues are:

    lambda_1 = -1 and lambda_2 = 3

    for lambda_1 = -1: 2*k1 + 2*k2 = 0
    k1 = -k2

    when k1 = 1, k2 = - 1 the related eigenvector is (1; -1)


    for lambda_2 = 3: -2*k1 + 2*k2 = 0
    k1 = k2

    when k1 = 1, k2 = 1 the eigenvector is K2 = (1; 1)

    since the matrix of coefficeints is a 2x2 matrix and since we found two linearly independent solutions,

    the general solution of the system is:

    X = c1*X1 + c2*X2 = c1*(1;-1)*exp(-t) + c2*(1; 1)*exp(t)
    or
    x = c1*exp(-t) + c2*exp(t)
    y = -c1*exp(-t) + c2*exp(t)

    We can classify the origin as neither a repeller nor an attractor.

    Is this correct?

    Also I feel like I need to provide more information when classifying the origin but I don't know what. For instance should I call the origin a saddle point because it has eigenvalues of different polarities?
     

    Attached Files:

  2. jcsd
  3. Nov 9, 2011 #2
    The origin is a saddle. Also, I think you should draw a better phase portrait showing the flow in all four quadrants. Here's the code if you wish to do so in Mathematica but I don't think you can run it in Alpha:

    StreamPlot[{x+2y,2x+y},{x,-2,2},{y,-2,2}]
     
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