Solving for Resistance and EMF in a Circuit

  • Thread starter Thread starter BuBbLeS01
  • Start date Start date
  • Tags Tags
    Emf Resistance
Click For Summary

Homework Help Overview

The discussion revolves around determining the resistance (R) and electromotive force (emf) of a circuit with given values for current and resistance. The problem involves applying Ohm's law and circuit analysis principles.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss setting up equations based on current and voltage relationships in the circuit. There are attempts to express the relationships between resistance, current, and emf, with some participants questioning the correctness of their equations.

Discussion Status

The discussion is ongoing, with participants exploring different equations and approaches to isolate R. Some guidance has been provided regarding algebraic manipulation, but there is no consensus on the correct method or solution yet.

Contextual Notes

Participants express confusion regarding the setup of equations and the use of resistor names in the circuit. There is also mention of needing to show work for homework purposes.

BuBbLeS01
Messages
602
Reaction score
0

Homework Statement



2d7hlhc.jpg


What is the resistance R? (R1=15.13 Ω, I1=2.77 mA , I2=1.81 mA. Give answer in Ω.)
What is the emf of the battery?

Homework Equations



I = E/R

The Attempt at a Solution



How do I solve this with the batteries EMF?
 
Physics news on Phys.org
Write 2 equations with the two unknowns (V and R), then solve for both.

And shrink that picture!
 
Ok let me see what I can come up with...
How do you shrink it? I did it on tinypic.com
 
E = -v1 - V2
E = Ir1 + Ir2
R = E/i
 
BuBbLeS01 said:
Ok let me see what I can come up with...
How do you shrink it? I did it on tinypic.com

With Paint or other figure manipulation/drawing programs, you can choose to "Save As" and specify the resolution.
 
Are those the right equations? I am not seeing how to solve this?
 
BuBbLeS01 said:
E = -v1 - V2
E = Ir1 + Ir2
R = E/i

Write one equation for the current and voltage in the middle branch, and one equation for the current and voltage in the right branch.
 
MIDDLE BRANCH:
R = E/I

RIGHT BRANCH:
R = E/I1 + I2

That doesn't look right??
 
BuBbLeS01 said:
MIDDLE BRANCH:
R = E/I

RIGHT BRANCH:
R = E/I1 + I2

That doesn't look right??

Why are you not using the names of the resistors in the figure? There are two resistors in the right branch, correct? And current J1 flows in the left branch, and J2 flows in the right branch. Both branches have the same voltage across them, correct?

Take your time and think it out. I need to bail -- you'll get it (or more help may stop by if you have more questions).
 
  • #10
MIDDLE BRANCH:
R = E/I1

RIGHT BRANCH:
R + R1= E/I2

Is that right?
 
  • #11
Ok so I think I got it...I just set them equal to each other and I get...
I1 * R = (R + R1) * I2
But for some reason I don't know how to solve for R! I can't figure it out...very sad...please help me! I have tried all sorts of things and I am not getting anywhere...
 
  • #12
can anyone help me with this part?
 
  • #13
I1 * R = (R + R1) * I2
Substitute the values of I1, I2 and R1 and solve for R
 
  • #14
Thats what I am trying to do but I can't figure out how to get the R by itself on one side since there are 2 of them. I always end up with R/R which is just 1. Its not making sense to me.
 
  • #15
Do you already know what the answer is suppose to be? We use to get the solution to some of our problems, but had to show the work in getting to it.

Do you end up with R*(2.77) = R*(1.81) + (27.39) ?
 
  • #16
No I don't know what the answer should be
 
  • #17
BuBbLeS01 said:
Ok so I think I got it...I just set them equal to each other and I get...
I1 * R = (R + R1) * I2
But for some reason I don't know how to solve for R! I can't figure it out...very sad...please help me! I have tried all sorts of things and I am not getting anywhere...

It's simple algebra. Distribute I2 on the right side into the parenthesis. That gives you one R term on the left and one R term on the right, with the additional R1*I2 term on the right. Just move the R term from the right side to the left (you do know how to do that, right?), and then finish solving for R all by itself.

Please try again, and show each of your steps here.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
4
Views
2K